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Alex
2 years ago
10

A 60 N force is applied over a distance of 15 m. How much work was done?

Physics
1 answer:
GuDViN [60]2 years ago
3 0

Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

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A trained eye in the dark for an extended period of time may pick up a light stimulus from a light source, at the lowest radiate
frez [133]

Answer:

    #_photons = 30 photons / s

Explanation:

Let's start by finding the energy of a photon of light, let's use the Planck relation

         E = h f

the speed of light is related to wavelength and frequency

         c = λ f

we substitute

         E = h c /λ

         E₀ = 6.63 10⁻³⁴ 3 10⁸/500 10⁻⁹

         E₀ = 3.978 10⁻¹⁹ J

now let's use a direct proportion rule. If the energy of a photon is Eo, how many fornes has an energy E = 1.2 10⁻¹⁷ J in a second

          #_photons = 1 photon   (E / Eo)

          #_photons = 1  1.2 10⁻¹⁷ /3.978 10⁻¹⁹

          #_photons = 3.0 10¹

          #_photons = 30 photons / s

3 0
2 years ago
A 1-kg rock is suspended from the tip of a horizontal meterstick at the 0-cm mark so that the meterstick barely balances like a
tigry1 [53]

Explanation:

Given that,

Mass if the rock, m = 1 kg

It is  suspended from the tip of a horizontal meter stick at the 0-cm mark so that the meter stick barely balances like a seesaw when its fulcrum is at the 12.5-cm mark.

We need to find the mass of the meter stick. The force acting by the stone is

F = 1 × 9.8 = 9.8 N

Let W be the weight of the meter stick. If the net torque is zero on the stick then the stick does not move and it remains in equilibrium condition. So, taking torque about the pivot.

9.8\times 12.5=W\times (50-12.5)\\\\W=\dfrac{9.8\times 12.5}{37.5}

W = 3.266 N

The mass of the meters stick is :

m=\dfrac{W}{g}\\\\m=\dfrac{3.266}{9.81}\\\\m=0.333\ kg

So, the mass of the meter stick is 0.333 kg.

5 0
3 years ago
Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo
olya-2409 [2.1K]

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

7 0
3 years ago
How does solar energy produce electricity?
elena-14-01-66 [18.8K]
By the use of "Solar cells" or "Solar panel", we can trap solar energy in silicon/germanium rods, then we can convert in into electricity too.

Hope this helps!
8 0
2 years ago
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
grigory [225]

Given that,

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.

To find,

The distance from the source would the sound level be one-fourth the sound level at 3.00 m.

Solution,

The intensity from a source is inversely proportional to the distance.

Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?

Using relation :

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m

So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.

8 0
2 years ago
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