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ser-zykov [4K]
1 year ago
14

Given 3.5M and 10.5ml of zn(oh)2 find the molarity of nitric acid given 15.0 ml of nitric acid

Chemistry
1 answer:
lana [24]1 year ago
8 0

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

<h3>What is molarity?</h3>

It is a unit of concentration equivalent to moles of solute per liter of solution.

  • Step 1: Write the balanced equation.

Zn(OH)₂ + 2 HNO₃ ⇒ Zn(NO₃)₂ + 2 H₂O

  • Step 2: Calculate the reacting moles of Zn(OH)₂.

10.5 mL of 3.5 M Zn(OH)₂ react.

0.0105 L × 3.5 mol/L = 0.037 mol

  • Step 3: Calculate the reacting moles of HNO₃.

The molar ratio of Zn(OH)₂ to HNO₃ is 1:2.

0.037 mol Zn(OH)₂ × 2 mol HNO₃/1 mol Zn(OH)₂ = 0.074 mol HNO₃

  • Step 4: Calculate the molarity of HNO₃.

[HNO₃] = 0.074 mol / 0.0150 L = 4.9 M

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

Learn more about molarity here: brainly.com/question/26873446

#SPJ1

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Barium nitrate has the formula Ba( NO3)2. Which statement is true about barium nitrate?
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I found these four statements for that question:

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The last one is true. Each molecule contains six oxygen atoms.
The number to the right of O and of (NO3) ares subscripts.


The chemical formula uses subscripts to indicate the number of atoms.



The subscript 2 in (NO3)2 means that there are two NO3 radicals.


And the subscript 3 to the right of O means that each NO3 radical has three atoms of O.

Then, the number of atoms of O is 2 * 3 = 6.


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Explanation:

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