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ser-zykov [4K]
1 year ago
14

Given 3.5M and 10.5ml of zn(oh)2 find the molarity of nitric acid given 15.0 ml of nitric acid

Chemistry
1 answer:
lana [24]1 year ago
8 0

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

<h3>What is molarity?</h3>

It is a unit of concentration equivalent to moles of solute per liter of solution.

  • Step 1: Write the balanced equation.

Zn(OH)₂ + 2 HNO₃ ⇒ Zn(NO₃)₂ + 2 H₂O

  • Step 2: Calculate the reacting moles of Zn(OH)₂.

10.5 mL of 3.5 M Zn(OH)₂ react.

0.0105 L × 3.5 mol/L = 0.037 mol

  • Step 3: Calculate the reacting moles of HNO₃.

The molar ratio of Zn(OH)₂ to HNO₃ is 1:2.

0.037 mol Zn(OH)₂ × 2 mol HNO₃/1 mol Zn(OH)₂ = 0.074 mol HNO₃

  • Step 4: Calculate the molarity of HNO₃.

[HNO₃] = 0.074 mol / 0.0150 L = 4.9 M

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

Learn more about molarity here: brainly.com/question/26873446

#SPJ1

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Answer:

0.01931034

Explanation:

Steps:

ρ =  m/v

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28 gram

1.45 cubic meter

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HELPP
slamgirl [31]

Answer:

In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.

Explanation:

tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:

\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=

mass compound

mass H

×100%

\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=

mass compound

mass C

×100%

If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:

\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=

10.0g compound

2.5g H

×100%=25%

\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=

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7 0
3 years ago
Regular copyright is more restrictive than any other kind of license. true or flase
GREYUIT [131]

The correct answer is true

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3 years ago
Based on periodic trends of electronegativity, what statement regarding the halogens is MOST accurate?
8090 [49]

Answer:

C) Fluorine has the strongest tendency to attract electrons.

Explanation:

Electronegativity is the tendency of the atom in a covalent bond to attract the shared pair of electron towards itself.

Down the group, size increases which means that the nucleus become far from the valence electrons and thus decreased electronegativity as there will be less tendency to attract the shared electrons.

Fluorine and iodine are in the same group and thus fluorine has higher tendency to attract electrons and thus has the highest electronegativity.

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3 years ago
If 11.2 g of naphthalene, C10H8, is dissolved in 107.8 g of chloroform, CHCl3, what is the molality of the solution?
Art [367]

Answer: 0.811m

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11.2g C10H8 = 11.2/128.17 g/mol C10H8

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NOW 107.8g solvent (chloroform) contains 0.0879 molecules (naphthalene)

1000g   ''    will contain (0.0879/107.8 x 1000) mole solute

= 0.811 mole

Molarity of the solution is 0.811 m (option A)

5 0
3 years ago
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