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ser-zykov [4K]
1 year ago
14

Given 3.5M and 10.5ml of zn(oh)2 find the molarity of nitric acid given 15.0 ml of nitric acid

Chemistry
1 answer:
lana [24]1 year ago
8 0

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

<h3>What is molarity?</h3>

It is a unit of concentration equivalent to moles of solute per liter of solution.

  • Step 1: Write the balanced equation.

Zn(OH)₂ + 2 HNO₃ ⇒ Zn(NO₃)₂ + 2 H₂O

  • Step 2: Calculate the reacting moles of Zn(OH)₂.

10.5 mL of 3.5 M Zn(OH)₂ react.

0.0105 L × 3.5 mol/L = 0.037 mol

  • Step 3: Calculate the reacting moles of HNO₃.

The molar ratio of Zn(OH)₂ to HNO₃ is 1:2.

0.037 mol Zn(OH)₂ × 2 mol HNO₃/1 mol Zn(OH)₂ = 0.074 mol HNO₃

  • Step 4: Calculate the molarity of HNO₃.

[HNO₃] = 0.074 mol / 0.0150 L = 4.9 M

10.5 milliliters of 3.5 M zinc hydroxide react completely with 15.0 milliliters of 4.9 M nitric acid.

Learn more about molarity here: brainly.com/question/26873446

#SPJ1

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Write equations for the following: (b) an addition reactionbetween cyclohexene and Cl₂;
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The required equation for an addition reaction between cyclohexene and Cl2 .

Cyclohexene + Cl2 → 1,2-dichlorocyclohexane

What is addition reaction ?

it is type of reaction in which one molecule combines with another molecule to form larger molecules .

addition reaction types are electrophilic , nucleophilic and free radical addition reaction .

<h3>What is free radical addition reaction ?</h3>

it is type of addition reaction where functional group is added to a compound through a free radical intermediate .

The free radical addition reaction involves chain initiation , chain propagation and chain termination .

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Which of these might affect whether or not a particular chemical reaction occurs?
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1.5 moles of Al is how many<br> atoms?
aev [14]

Answer:

<h2>9.03 × 10²³ atoms </h2>

Explanation:

The number of atoms of Al can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ atoms</h3>

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