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andriy [413]
3 years ago
6

Create a balanced equation of this COMBUSTION REACTION: C8H18 (hint, all combustion reactions have some things in common (CO2 an

d H2O). Show all work leading up to balanced equation, step by step, INCLUDING A SCOREBOARD that shows individual atom count before and after. (Reactants in Green and Products in Red)
Chemistry
1 answer:
julsineya [31]3 years ago
8 0
2C8H18+72O2>>16CO2+36H2O<< balanced
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What is the molar mass of a 3.228 g sample of a gas if it occupies 3.21 L at 298 K and 1.25 atm?
IrinaK [193]

Taking into account the ideal gas law and the definition of molar mass, the molar mass of a 3.228 g sample of a gas if it occupies 3.21 L at 298 K and 1.25 atm is 19.66 \frac{g}{moles}.

<h3 /><h3>What is ideal gas law</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

<h3 /><h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Number of moles in this case</h3>

In this case, you know:

  • P= 1.25 atm
  • V= 3.21 L
  • n= ?
  • R= 0.082 \frac{atmL}{mol K}
  • T= 298 K

Replacing in the ideal gas law:

1.25 atm× 3.21 L = n× 0.082 \frac{atmL}{mol K}× 298 K

Solving:

n= (1.25 atm× 3.21 L)÷ (0.082 \frac{atmL}{mol K}× 298 K)

<u><em>n= 0.1642 moles</em></u>

So, the number of moles in this case are 0.1642 moles.

<h3>Molar mass of the sample</h3>

In this case, you know:

  • mass= 3.228 g
  • number of moles= 0.1642 moles

Then, considering the definition of molar mass, it is calculated as:

molar mass=\frac{3.228 g}{0.1642 moles}

Solving:

<u><em>molar mass= 19.66</em></u>\frac{g}{moles}<em />

Finally, the molar mass of a 3.228 g sample of a gas if it occupies 3.21 L at 298 K and 1.25 atm is 19.66 \frac{g}{moles}.

Learn more about

ideal gas law:

<u>brainly.com/question/4147359</u>

molar mass:

brainly.com/question/5216907

<u>brainly.com/question/11209783</u>

<u>brainly.com/question/7132033</u>

<u>brainly.com/question/17249726</u>

5 0
2 years ago
Suppose 20.8 g of sodium iodide is dissolved in 250. mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mola
gtnhenbr [62]

Answer:

[Ag+] = [NO3-] = 0.700M

0.555M = [Na+] = [I-]

Explanation:

To solve this question we need to find the moles of sodium iodide, NaI, using its molar mass -. With the moles and the volume we can find the molarity of Na+ and I-. The molarity of the ions of silver nitrate, AgNO3 doesn't change because we are assuming the volume doesn't change:

<em>Molarity Ag⁺ = Molarity NO₃⁻ = 0.700M</em>

<em>Moles NaI -Molar mass: 149.89g/mol-</em>

20.8g NaI * (1mol/149.89g) = 0.0139 moles NaI

<em>Molarity:</em>

0.0139 moles NaI / 0.250L = <em>0.555M = [Na+] = [I-]</em>

7 0
2 years ago
Differentiate between acids and bases on the basis of their pH values. Give an example of each type. (ANSWER ASAP)
inessss [21]

Acid and bases both are the substances that cause corrosion. They can be differentiated on the basis of properties and pH.

If the pH is less than 7.0 the solution is acidic while if its value is greater than 7.0 it is the basis solution.

Examples:

Acid

Acetic acid has pH value 2.4

Sulphuric acid has pH value 0 for 1M solution

Base

pH of ammonia solution is 11


4 0
3 years ago
The__is the source of energy used in photosynthesis?
kolezko [41]

Answer:

sun

Explanation:

source means where it comes from and the source of energy comes from the sun

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An ordered list of chemical substances is shown.
Alex73 [517]

answer : the correct option is, (B) 2, 3 and 6.

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