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Need alot of help please
1 answer:
Answer:
a) linear
b) nonlinear
c) nonlinear
d) nonlinear
Step-by-step explanation:
For a linear equation the highest degree is 1. If the degree is more than 1, then it is a non-linear equation.
a) 7x=y-4 is a linear equation because the highest degree is one
b)
is not a linear equation because when we multiply through by x, we get
The degree is 2
c) 6xy +3x=2 is non linear because the degree is 2.
d) x=2y³ +y is non-linear be because the degree is 3.
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Answer:
The 99% confidence interval is (3.0493, 3.4907).
We are 99% sure that the true mean of the students Perry score is in the above interval.
Step-by-step explanation:
Our sample size is 21.
The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So
.
Then, we need to subtract one by the confidence level and divide by 2. So:
Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have
Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So
Now, we multiply T and s
Then
The lower end of the interval is the mean subtracted by M. So:
The upper end of the interval is the mean added to M. So:
The 99% confidence interval is (3.0493, 3.4907).
Interpretation:
We are 99% sure that the true mean of the students Perry score is in the above interval.
Answer:
a) 96.64% probability that maximum speed is at most 50 km/h
b) 24.67% probability that maximum speed is at least 48 km/h
c) 86.64% probability that maximum speed differs from the mean value by at most 1.5 standard deviations
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
A. What is the probability that maximum speed is at most 50 km/h?
This is the pvalue of Z when X = 50. So
has a pvalue of 0.9664
96.64% probability that maximum speed is at most 50 km/h.
B. What is the probability that maximum speed is at least 48 km/h?
This is 1 subtracted by the pvalue of Z when X = 48.
has a pvalue of 0.7533
1 - 0.7533 = 0.2467
24.67% probability that maximum speed is at least 48 km/h.
C. What is the probability that maximum speed differs from the mean value by at most 1.5 standard deviations?
Z = 1.5 has a pvalue of 0.9332
Z = -1.5 has a pvalue of 0.0668
0.9332 - 0.0668 = 0.8664
86.64% probability that maximum speed differs from the mean value by at most 1.5 standard deviations