The ionization of the following acids and bases can be expressed as follows :
(A ) HI + water →← H + (aq) + I -(aq)
(B) KOH + H2O →← K+(aq) + OH- (aq)
(C)HNO2(l) + H2O →← H+(aq) +NO2-(aq)
(D)H2PO4- + H2O →← H + (aq) + HPO4 ^2- (aq)
(E)CHNH2 + H2O→← CH3NH3+(aq) + OH-(aq)
(F)CH3CH2COOH +H2O→←CH3CH2COO-(aq) + H3O+(aq)
Cotton I grow nylon is made and wool is from a animal
They are all the same because they are all materials that are used in clothing
Answer:1
Explanation: friction is showing us how in the past
Answer:
[HAc] = 0.05M
[Ac⁻] = 0.20M
Explanation:
The Henderson-Hasselbalch formula for the acetic acid buffer is:
pH = pka + log₁₀ [Ac⁻] / [HAc]
Replacing:
5.36 = 4.76 + log₁₀ [Ac⁻] / [HAc]
3.981 = [Ac⁻] / [HAc] <em>(1)</em>
Also, as total concentration of buffer is 0.25M it is possible to write:
0.25M = [Ac⁻] + [HAc] <em>(2)</em>
Replacing (2) in (1)
3.981 = 0.25M - [HAc] / [HAc]
3.981 [HAc] = 0.25M - [HAc]
4.981 [HAc] = 0.25M
<em>[HAc] = 0.05M</em>
Replacing this value in (2):
0.25M = [Ac⁻] + 0.05M
<em>[Ac⁻] = 0.20M</em>
I hope it helps!