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Maslowich
4 years ago
13

If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul

d happen to the pressure of gas
Chemistry
2 answers:
True [87]4 years ago
5 0
The pressure of the gas would increase.

When gas is transported from a larger area to a smaller area it begins to increase in pressure.

Hope I could help, have a good one!
djyliett [7]4 years ago
3 0

Explanation:

According to Boyle's law, at constant temperature and constant number of moles  volume will be inversely proportional to pressure applied on a substance.

Mathematically,         Volume \propto \frac{1}{\text{pressure}}

Therefore, it means that decrease in volume will increase the pressure and vice-versa.

Hence, we can conclude that if a gas is moved from a large container to a small container but its temperature and number of moles remain the same, then there will be increase in the pressure of gas.

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What term do we use to describe a solution's ability to change the volume of a cell?
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The answer is tonicity
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4 years ago
Write equations that show the ionization of the following acids and bases.A) HIB) KOHC) HNO2D) H2PO4-E) CH3NH2F) CH3CH2COOH
OverLord2011 [107]

The ionization of the following acids and bases can be expressed as follows :

(A ) HI + water →← H + (aq) + I -(aq)

(B) KOH + H2O →← K+(aq) + OH- (aq)

(C)HNO2(l) + H2O →← H+(aq) +NO2-(aq)

(D)H2PO4- + H2O →← H + (aq) + HPO4 ^2- (aq)

(E)CHNH2 + H2O→← CH3NH3+(aq) + OH-(aq)

(F)CH3CH2COOH​ +H2O→←CH3CH2COO-(aq) + H3O+(aq)

4 0
1 year ago
1. How are Cotton, Nylon and Wool different ?<br><br> 2. How are Cotton, Nylon and Wool similar ?
nika2105 [10]

Cotton I grow nylon is made and wool is from a animal

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6 0
3 years ago
Read 2 more answers
True or false
Fittoniya [83]

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7 0
3 years ago
Calculate the concentration of acetic acid, HAc, and acetate ion, Ac−, in a 0.25M acetate buffer solution with pH = 5.36. "0.25M
Neporo4naja [7]

Answer:

[HAc] = 0.05M

[Ac⁻] = 0.20M

Explanation:

The Henderson-Hasselbalch formula for the acetic acid buffer is:

pH = pka + log₁₀ [Ac⁻] / [HAc]

Replacing:

5.36 = 4.76 + log₁₀ [Ac⁻] / [HAc]

3.981 = [Ac⁻] / [HAc] <em>(1)</em>

Also, as total concentration of buffer is 0.25M it is possible to write:

0.25M =  [Ac⁻] + [HAc] <em>(2)</em>

Replacing (2) in (1)

3.981 = 0.25M - [HAc] / [HAc]

3.981 [HAc] = 0.25M - [HAc]

4.981 [HAc] = 0.25M

<em>[HAc] = 0.05M</em>

Replacing this value in (2):

0.25M =  [Ac⁻] + 0.05M

<em>[Ac⁻] = 0.20M</em>

I hope it helps!

7 0
4 years ago
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