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zysi [14]
3 years ago
10

What volume is used to calculate the volume of a solid object ​

Chemistry
1 answer:
Degger [83]3 years ago
3 0

Answer:

cubic measurements

Explanation:

i.e. cubic meter or cubic centimeter

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Physical Science pre-Test 2020-2021
poizon [28]

Answer:

exothermic I think

Explanation:

IM TWKIGN THE TEST

4 0
3 years ago
Using Argn (n= –2, –1, 0, +1, +2, etc.) to represent the different charge species of Arginine, what is the dominant species of A
fredd [130]

Answer:

Explanation:

From the sorensen equation; pH = -Log[H+]

2.7 = -Log[H+]

H+ = 10^-2.7

H+ = 0.001995M = Hydrogen ion concentration

Basically, the more the charges, the higher the hydrogen ion concentration stand vice versa. +2 has the highest concentration.

6 0
3 years ago
A 270.0 gram piece of copper is dropped into 300.0 grams of water 24.00 °C. If the final temperature of water is 42.00 °C, what
Papessa [141]

Answer:

257

Explanation:

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4 0
3 years ago
calculate the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom?
inessss [21]

<u>Answer:</u>

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}

\Delta E=-1312[0.111-1]KJ mol^{-1}

\Delta E=1166 KJ mol^{-1}

\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}

=193623 \times 10^{-23}  \frac {J}{photon}

\Delta E=1.93623 \times 10^{-18}  \frac {J}{photon}

\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}

h is planck's constant  

c is the speed of light

λ is the wavelength of light  

\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18}  J/photon)}

Wavelength

\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m}  =103 nm (Answer)

<em>Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is </em><u><em>103 nm.</em></u>

7 0
3 years ago
Indicate the number corresponding to each coefficient required to write the balanced equation for the reaction:
dimaraw [331]
The number  of corresponding to each coefficient  required to write the balanced  equation for the  reaction is as below


2 HNO3  + Mg(OH)2  =  2H2O  + Mg(NO3)2
the  coefficient  is therefore
a=2
b=1
c=2
d=1

2 moles of HNO3  reacted  with 1  mole of Mg(OH)2   to form 2 moles of H2O  and 1 mole of Mg(NO3)2
5 0
3 years ago
Read 2 more answers
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