Answer: The layers of the rocks in one region of the parks are smooth and distinct, which are evidence of many, many years of deposition. The layers on the rocks are because of different deposition of sediments. Different sediments deposited over the rocks through wind, water and ice over the ages
Explanation:
Answer:
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
Explanation:
The equation used to calculate the constant for first order kinetics:
.....(1)
Rate law expression for first order kinetics is given by the equation:
![t=\frac{2.303}{k}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
......(2)
where,
k = rate constant
=Half life of the reaction = 
t = time taken for decay process = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the reactant = 0.163 M
[A] = amount left after time t = 66.8% of
[A]=
t = 1,409.19 s
1 minute = 60 sec
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
The question is incomplete , the complete question is;
The mass of each Wt isotope is measured relative to C-12 and tabulated below. Use the mass of C-12 to convert each of the masses to amu and calculate the atomic mass of Wt.
Wt-296 = 24.6622
Answer:
The atomic mass of Wt-296 is 195.9464 amu.
Explanation:
1 amu is defined as 1 by twelfth of the carbon-12 mass.
Mass of an isotope Wt-296 = 24.6622
Mass of an isotope Wt-296 in amu = M
The atomic mass of Wt-296 is 195.9464 amu.
All the information is answered/given in the paragraph except that the study doesn’t show cells in their natural habitat!
Answer:
²³⁸₉₂U has 146 neutrons
Explanation:
To know which option is correct, we shall determine the number of neutrons in each case. This can be obtained as follow:
For ²⁴₁₂Mg:
Mass number (A) = 24
Proton number (P) = 12
Neutron number (N) =?
A = P + N
24 = 12 + N
Collect like terms
N = 24 – 12
N = 12
Thus, there are 12 neutrons in ²⁴₁₂Mg
For ⁷⁵₃₃As:
Mass number (A) = 75
Proton number (P) = 33
Neutron number (N) =?
A = P + N
75 = 33 + N
Collect like terms
N = 75 – 33
N = 42
Thus, there are 42 neutrons in ⁷⁵₃₃As
For ¹⁹₉F:
Mass number (A) = 19
Proton number (P) = 9
Neutron number (N) =?
A = P + N
19 = 9 + N
Collect like terms
N = 19 – 9
N = 10
Thus, there are 10 neutrons in ¹⁹₉F.
For ²³⁸₉₂U:
Mass number (A) = 238
Proton number (P) = 92
Neutron number (N) =?
A = P + N
238 = 92 + N
Collect like terms
N = 238 – 92
N = 146
Thus, there are 146 neutrons in ²³⁸₉₂U
Considering the options and the illustration made above, Only ²³⁸₉₂U has the correct number of neutrons written along side.
