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olya-2409 [2.1K]
3 years ago
14

An alkane with the formula C6H14 can be prepared by hydrogenation of either of two precursor alkenes having the formula C6H12. W

rite the structure of this alkane.
Chemistry
1 answer:
EleoNora [17]3 years ago
8 0
            
             H  H H H H H
              |   |   |   |   |   |
         H-C-C-C-C-C-C-H  
              |   |   |   |   |   | 
             H  H H H H H
This is the structural formula for C6H14. Every carbon atom in the molecule must be surrounded by four bonds. Hope this answers your question. 



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To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

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Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

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Volume of solution = 503.4 mL = 0.5034 L

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0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

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Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

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