Answer:
F = 2.40 × 
N
Explanation:
given data
charge q1 = 3.95 nC
x= 0.198 m
charge q2 = 4.96 nC
x= -0.297 m
solution
force on a point charge kept in electric field F = E × q ................1
here E is the magnitude of electric field and q is the magnitude of charge
and
first we will get here electric field at origin
So net field at origin is
E = (Kq2÷r2²) - (kq1÷r1²) ...............2
put here value
E = 9[(4.96÷0.297²)-(3.95÷0.198²)]
E = 400.72 N/C ( negative x direction )
so that force will be
F = 6 × 
× 400.72
F = 2.40 × N
Answer:
Yes, correct
Explanation:
velocity, v = 470 m/s
radius, r = 0.15 m
The radial acceleration is the centripetal acceleration which always acts towards the centre of the circular centrifuge.
The formula for the centripetal acceleration is given by
a = 1472666.667
a = 150272.1 g
According to the question, we can get the acceleration as mentioned. So the claim is correct.
F equals 3N with respect to the circle's center, moving in the same direction as the centripetal acceleration.
<h3>How much centripetal force is there in a centrifuge?</h3>
Centripetal force is the force that pushes an item in the direction of its center of curvature. It is fundamental to how a centrifuge operates.
<h3>On a roller coaster, what is centripetal force?</h3>
An item travelling in a circle is pushed inward toward what is known as the center of rotation, which is essentially what a roller coaster accomplishes when it travels through a loop. The force that maintains an object moving along a curved route is this pull toward the center, or centripetal force.
To know more about centripetal force visit:-
brainly.com/question/11324711
#SPJ4
The answer is going to be B
