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fiasKO [112]
3 years ago
8

1. Uranium-238 decays by giving off one particle, and the decay can be represented by the following nuclear equation: 92238U 902

34Th + __________.
• What is the complete equation?
• What type of radiation is given off in this reaction?
• Where does it come from?
Hint: What is an alpha particle
Physics
1 answer:
const2013 [10]3 years ago
7 0
The complete equation is: 92238U --> 90234Th + 42He

This type of radiation is alpha decay in which an alpha particle is a Helium nucleus with 2 protons and 2 nuetrons. This nucleus/alpha particle(s) are released to stabilize the radioactive atom, in this case, the 92238Uranium. 
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Nataly_w [17]

Explanation:

The given data is as follows.

      C_{1} = 1.50 \times 10^{-6} F

      C_{1} = 3.50 \times 10^{-6} F    

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Hence, calculate the equivalence capacitor as follows.

    \frac{1}{C} = \frac{1}{C_{1}} + \frac{1}{C_{2}}

    \frac{1}{C} = \frac{1}{1.50 \times 10^{-6} F} + \frac{1}{3.50 \times 10^{-6} F}

                 = 0.945 \times 10^{-6} F

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Now, we will calculate the charge across each capacitance as follows.

              Q = CV

                  = 1.06 \times 10^{-6} F \times 2.50 V

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Thus, we can conclude that 2.65 \mu C is the charge stored on each given capacitor.

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3 years ago
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