1. Uranium-238 decays by giving off one particle, and the decay can be represented by the following nuclear equation: 92238U 902
1 answer:
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Answer:
true
Explanation:
Here we have assumed that increasing the mass of a glove will increase the surface area.
Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by
where
F = Force
A = Area to which the force is applied
So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.
Hence, the statement is true.
Answer:
20 hertz of frequency produced.
Explanation:
Here we will find frequency and period should be in second, here given: 0.05 seconds
using the formula:
Answer:
Explanation:
Applied force, F = 18 N
Coefficient of static friction, μs = 0.4
Coefficient of kinetic friction, μs = 0.3
θ = 27°
Let N be the normal reaction of the wall acting on the block and m be the mass of block.
Resolve the components of force F.
As the block is in the horizontal equilibrium, so
F Cos 27° = N
N = 18 Cos 27° = 16.04 N
As the block does not slide so it means that the syatic friction force acting on the block balances the downwards forces acting on the block .
The force of static friction is μs x N = 0.4 x 16.04 = 6.42 N .... (1)
The vertically downward force acting on the block is mg - F Sin 27°
= mg - 18 Sin 27° = mg - 8.172 ... (2)
Now by equating the forces from equation (1) and (2), we get
mg - 8.172 = 6.42
mg = 14.592
m x 9.8 = 14.592
m = 1.49 kg
Thus, the mass of block is 1.5 kg.
