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3 years ago

HELP, what are 2 chemical properties of Tungsten.

Physics

2 answers:

ANTONII [103]3 years ago

5 0

Answer:

Tungsten is a grey-white lustrous metal

Explanation:

Tungsten has the highest melting point and lowest vapor pressure of all metals, and at temperatures over 1650°C has the highest tensile strength. It has excellent corrosion resistance and is attacked only slightly by most mineral acids.

GarryVolchara [31]3 years ago

3 0

Answer:

Molybdenum and seaborgium

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If a 1.3 kg mass stretches a spring 4 cm, how much will a 5.8 kg mass stretch the

Likurg_2 [28]

Answer:

17.8cm

Explanation:

1.3kg --> 4cm

1kg --> 3, 1/13cm

5.8kg --> 18.8cm

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2 years ago

Satellite A has an orbital radius 3.00 times greater than that of satellite B. Satellite B's orbital period around Earth is 120

igomit [66]

Answer:

To find the circumference (orbit) of an object, you use Pi x Diameter.

As you have the circumference of B, you divide it by Pi to get the Diameter.

So 120 divided by 3.141592654 = 38.2 minutes for the Diameter.

As' radius and Diameter will be 3x greater than B.

38.2 x 3 = 114.6

To get back to the orbital period, times 114.6 by Pi, and you will get 360 minutes

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

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7 0

3 years ago

Which uses motion of water in nature to produce electricity?

Zinaida [17]

Answer: D. Hydroelectric power

Explanation: Hydroelectric means water power (not exactly but "hydro" is water and electric is well self explanatory)

6 0

3 years ago

What are four minerals that are commonly taken from ores

Umnica [9.8K]

If it helps or doesn't I'm sorry, but if you even played the game Minecraft just remember it.

Gold, silver, coal, and iron come from ores.

5 0

3 years ago

The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east.

Elena L [17]

Answer:

The magnitude of the acceleration is $a_r = 1.50 \ m/s^2$

The direction is $\theta = 32.5 6^o$ north of east

Explanation:

From the question we are told that

The force exerted by the wind is $F_{sail} = (330 ) \ N \ north$

The force exerted by water is $F_{keel} = (210 ) \ N \ east$

The mass of the boat(+ crew) is $m_b = 260 \ kg$

Now Force is mathematically represented as

$F = ma$

Now the acceleration towards the north is mathematically represented as

$a_n = \frac{F_{sail}}{m_b}$

substituting values

$a_n = \frac{330 }{260}$

$a_n = 1.269 \ m/s^2$

Now the acceleration towards the east is mathematically represented as

$a_e = \frac{F_{keel}}{m_b }$

substituting values

$a_e = \frac{210}{260}$

$a_e =0.808 \ m/s^2$

The resultant acceleration is

$a_r = \sqrt{a_e^2 + a_n^2}$

substituting values

$a_r = \sqrt{(0.808)^2 + (1.269)^2}$

$a_r = 1.50 \ m/s^2$

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

$tan \theta = \frac{a_e}{a_n}$

$\theta = tan ^{-1} [\frac{a_e}{a_n } ]$

substituting values

$\theta = tan ^{-1} [\frac{0.808}{1.269 } ]$

$\theta = tan ^{-1} [0.636 ]$

$\theta = 32.5 6^o$

5 0

3 years ago