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erma4kov [3.2K]
2 years ago
10

The terms sanity and insanity:

Physics
2 answers:
Alex Ar [27]2 years ago
6 0

Answer:

are definitions that are used in the legal system

Explanation:

  ap3x bruv :)

IgorLugansk [536]2 years ago
3 0
Whats the question exactly?
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I will mark as the brainliest answer​
erastova [34]

Answer:

8) 1500 feet

9) 20 miles

10) 4 Days

11) 2250 miles

12) 1 hour and 5 minutes

13) 27.27miles per hour

Explanation

8) There are 60 seconds in one minute so 60x25=1500 feet

9) 30 minutes is half of an hour so 40 miles ÷ 2 = 20 miles

10) 12x4=48

11) 500 miles x 4.5 hours is 2250 miles

12) Train leaves at 3pm after 60 miles it will be 4 pm and after 5 more miles 4:05 pm so 1 hour and 5 minutes

13)

Elmo = 40 minutes and 5 miles

Bert and Ernie = 45 minutes and 15 miles

Cookie Monster = 20 minutes and 10 miles

Home = 5 minutes abd 20 miles

Average Speed including stops is 27.27 miles per hour

5 0
3 years ago
A car is traveling along a straight road at a velocity of +30.0 m/s when its engine cuts out. For the next 1.79 seconds, the car
Tanzania [10]

Answer:

first value+2nd +3rd

Explanation:

thug life and there

8 0
3 years ago
When did diesel locomotives replace steam locomotives?
liubo4ka [24]
To keep the energy going every day
7 0
3 years ago
A 1300 kg steel beam is supported by two ropes. (Figure
Dmitriy789 [7]

Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

By Newton's second law,

  • the net horizontal force acting on the beam is

R_1 \cos(110^\circ) + R_2 \cos(60^\circ) = 0

where R_1,R_2 are the magnitudes of the tensions in ropes 1 and 2, respectively;

  • the net vertical force acting on the beam is

R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0

where m=1300\,\rm kg and g=9.8\frac{\rm m}{\mathrm s^2}.

Eliminating R_2, we have

\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2

R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2

-R_1 \sin(50^\circ) = -\dfrac{mg}2

R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}

Solve for R_2.

\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0

\dfrac{R_2}2 = -mg\cot(110^\circ)

R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}

8 0
1 year ago
How is the lifetime of a star related to its mass?
Flauer [41]
Stars having less mass collapses early than those with more mass. This can be explained by Einstein's equation E=mc².
According to this equation, mass of stars is converted into light due to thermonuclear reactions occuring in the core of star which acts as engine of the stars. This thermonuclear reactions keeps star alive. Thermonuclear reactions occurs slowly in massive stars hence massive stars live more than light stars.
6 0
3 years ago
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