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3 years ago

If an electric circuit is not grounded, it is best to reach out and touch it to provide the ground

Physics

1 answer:

fgiga [73]3 years ago

5 0

Answer:

No. Touching a live electric current is never a good idea.

Explanation:

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What are the uses of nuclear fission or fusion and their benefits

tamaranim1 [39]

Answer: The uses of nuclear fission are nuclear activator utilize for mercantile electric-power alternator throughout the world and it also has powerful starting point for propelling submarines and certainly kinds of surface yacht. And about the fusion benefits, that is that the nuclear fusion has clean vigor, very low power source cost, along with other benefits.

Hopefully this helps you my dear friend! :-)

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4 years ago

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The diagram shows the layers of the Sun. Which labels correctly identify the layers most closely associated with gamma rays and

ipn [44]

Z - Gamma Rays
X - Visible Light

Gamma rays are heavily produced in the core of the sun but are diluted before they reach the surface (Z). And the surface is the only thing the human eye can see (X).

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3 years ago

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Is water (H2O) a element? why or why not?

Dafna1 [17]

No it is not an element, it is a compound(two ore more elements bound together). It is one Oxygen and two Hydrogen bound together by covalent bonds.

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4 years ago

Find the energy of one quantum of microwave radiation with frequency 4 GHz and with 500 GHz .

REY [17]

Answer:

1. $1.65*10^{-5} eV$ and $2.07*10^{-3}eV$ 2. $2.10*10^{-7}m$

Explanation:

The energy of a photon is given by the so-called Planck-Einstein relation:

$E=fh=\frac{ch}{\lambda}$

where E is the energy, f the frequency, $\lambda$ the wavelength, c the speed of light and h the planck constant

So, we have:

$E=fh\\E=(4*10^9Hz)(4.136*10^{-15}eV*s)=1.65*10^{-5} eV\\$

And:

$E=fh\\E=(5*10^{11}Hz)(4.136*10^{-15}eV*s)=2.07*10^{-3} eV\\$

2. The work function is the amount of energy required to remove an electron from the material. Therefore the kinetic energy of the photoelectrons will be the energy of the electromagnetic radiation minus the work function:

$K=E-W$

Where K is the kinetic energy and W the work function, for copper W=4.7eV

Rewriting for $\lambda$ :

$E=K+W\\\frac{ch}{\lambda}=K+W\\\lambda=\frac{ch}{K+W}\\\lambda=\frac{(3*10^8m/s)4.136*10^{-15}eV}{1.2eV+4.7eV}=2.10*10^{-7}m$

This wavelength corresponds to the ultraviolet range

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3 years ago

A father and his young son get on a teeter-totter. The son sits 2 m fromthe center, but the father has to sit closer to balance.

Luda [366]

Answer:

The distance of the father from the center is $d_f = \frac{1}{2} \ m$

Explanation:

From the question we are told that

The distance of the son from the center is $d_s = 2 \ m$

Let the mass of the son be $m_s$

then the mass of the father is $m_f = 4m_s$

Now for the teeter-totter to be balanced the torque due to the weight of the father must be equal to the torque due to the weight the son, this is mathematically represented as

$\tau_s = \tau_f$