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Vedmedyk [2.9K]
3 years ago
13

The diagram shows the layers of the Sun. Which labels correctly identify the layers most closely associated with gamma rays and

visible light?
Z: Gamma rays
X: Visible light

X: Gamma rays
Z: Visible light

Z: Gamma rays
Y: Visible light

Y: Gamma rays
Z: Visible light

Physics
2 answers:
ipn [44]3 years ago
3 0
Z - Gamma Rays
X - Visible Light

Gamma rays are heavily produced in the core of the sun but are diluted before they reach the surface (Z). And the surface is the only thing the human eye can see (X).
OLga [1]3 years ago
3 0

Answer:

Z: Gamma rays

X: Visible light

Explanation:

A close look at the diagram attach shows the core of the sun and then the external surface.

Gamma rays are intricately associated with the nuclear reactions that go on in the core of the sun that makes it to produce light. Hence Z must refer to gamma rays emitted in these nuclear processes at the core of the sun.

Visible light is given out by the sun and seen externally. Hence X is visible light.

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Consider a rocket that is in deep space and at rest relative to an inertial reference frame. The rocket's engine is to be fired
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Answer:

\frac{m_i}{m_f}=2.7182

\frac{m_i}{m_f}=1096.633

Explanation:

m_i = Initial mass of rocket

m_f = Final mass of rocket

u = Initial velocity

v_r = Relative velocity

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From the rocket equation

v=u+v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v}}=e^1\\\Rightarrow \frac{m_i}{m_f}=2.7182

\frac{m_i}{m_f}=2.7182

when v=7v_r

v=v_{r}\ln {\frac {m_{i}}{m_{f}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{v}{v_{r}}}\\\Rightarrow \frac{m_i}{m_f}=e^{\frac{7v_r}{v_r}}=e^7\\\Rightarrow \frac{m_i}{m_f}=1096.633

\frac{m_i}{m_f}=1096.633

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