Data:
Vo = 120 ft / s
α = 30°
t = 5 s
x = ?
Formulas:
cos(α) = Vo,x / Vo => Vo,x = Vo * cos(α)
x = Vo,x * t
Calculations:
Vo,x = 120 ft / s * cos(30) = 103.92 ft /s
x = 103.92 ft/s * 5 s = 519.6 ft
Answer: 519.6 ft
Answer:
Tension in the supporting cable is = 4,866 N ≅4.9 KN
Explanation:
First of all, we need to understand that tension is a force, so the motion law
F = Ma applies perfectly.
From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.
Parameters given:
Mass of load = 1650 kg
Acceleration of load = ?
The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.
Time taken = distance covered / velocity
= = 3.73 seconds
∴Acceleration = ( initial velocity - final velocity )/ time taken
Note: Final velocity is = 0 since the body came to a rest.
Acceleration = = 2.95m/
Force acting on the cable = mass of elevator × acceleration of elevator
= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN
Answer:
The wavelength of the emitted photon is 413.6 nm
Explanation:
Given;
energy of the emitted photon, E = 3 eV = 3 x 1.602 x 10⁻¹⁹ J
speed of light, c = 3 x 10⁸ m/s
The energy of the emitted photon is given by;
E = hf
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
f is the frequency of the light = c / λ
λ is the wavelength
Therefore, the wavelength of the emitted photon is 413.6 nm
Answer:
C is the best answer because we all know that clock is part of our daily lives but we don't know the about its background
Answer:
100 times
Explanation:
Question:
The cylinders of a hydraulic part are 15cm and 150cm in diameter. How many times will the force acting on the piston with the smaller diameter be multiplied?
Solution:
Smaller diameter = 15cm
Bigger diameter = 150cm
Using Pascal's principle
F/A = f/a
Pressure = Force/Area
Pressure on piston with bigger diameter = pressure on piston with smaller diameter
Let Pressure on piston with bigger diameter = P
P =F/A
pressure on piston with smaller diameter = p
p = f/a
F/A = f/a
F×a = f×A
F/f = A/a
Area = πr^2
F/f = [π×(150)^2]/ [π×(15)^2]
F/f = (150)^2/ (15)^2
F/f = 100
F = 100f
The force acting on the piston with the smaller diameter will be multiplied 100 times.