Answer:
derived units are units of measurement derived from the seven base units specified by the International System of Units.
Explanation:
By Newton's second law,
<em>n</em> + (-<em>w</em>) = 0
<em>p</em> + (-<em>f</em> ) = (20 kg) (2 m/s²)
where <em>n</em> is the magnitude of the normal force, <em>w</em> is the weight of the box, <em>p</em> is the magnitude of the applied force (<em>p</em> for <u>p</u>ush or <u>p</u>ull), and <em>f</em> is the magnitude of the friction force.
Calculate the weight of the box:
<em>w</em> = (20 kg) (9.80 m/s²) = 196 N
Then
<em>n</em> = <em>w</em> = 196 N
and
<em>f</em> = <em>µ</em> <em>n</em> = 0.5 (196 N) = 98 N
Now solve for <em>p</em> :
<em>p</em> - 98 N = 40 N
<em>p</em> = 138 N
P=W/t=2940/10=294 W
W=F•s
W=m•g•s
W=150×9.8×2
W=2940 J
Given:
object = 20kg
terminal speed of object = 80 m/s
According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
Answer:
the total acceleration decreases when a body falls until it reaches the value of zero.
Explanation:
In general, resistive forces always oppose the movement of bodies, when a body falls into the air it is subject to two forces, the gravitational attraction and the resistive force of the air that opposes this movement, this force is proportional to the speed and the size of the body increases its value until it equals the acceleration of gravity and from this moment the body moves with constant speed.
In summary, the total acceleration decreases when a body falls until it reaches the value of zero.