Ask question

Ask question

All categories

3 years ago

15

According to aristotle what kind of motion requires no force

1 answer:

Ivan3 years ago

3 0

natural motion is the motion that requires no force

You might be interested in

The Grand Canyon is more than 400 km long and in some places almost 2 km deep. Which model best represents the main process that

satela [25.4K]

Answer: Diagram A

Explanation:

The Grand Canyon was created by the constant flow of the Colorado river which physically broke down the rock for billions of years. It then carried off the rock as it flowed and as it kept doing this, the canyon kept getting deeper and deeper.

This is what is described in the first diagram. The water from the faucet is carrying the soil along with it much like the Colorado did to the rocks of the Grand Canyon.

5 0

3 years ago

A girl sits on a tire swing and is pushed in a circular motion by her father. Her tangential speed is 2.8 m/s and the girl trave

Jet001 [13]

Formula: Ca=Vt^2/r

centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m

Substitute: Ca=2.8^2/2
Ca=3.92m/s^2

3 0

3 years ago

Read 2 more answers

When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a

Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

Put the value into the formula

$\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}$

$\dfrac{1}{f}=-\dfrac{3}{110}$

$f=-36.6\ cm$

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

$\dfrac{1}{36.6}=\dfrac{1}{v}-\dfrac{1}{-110}$

Here, focal length is positive for converging lens

$\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}$

$\dfrac{1}{v}=\dfrac{367}{20130}$

$v=54.85\ cm$

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

5 0

3 years ago

A 2-Newton upward net force is being applied to a 10-kg object. What is the magnitude of the upward

Colt1911 [192]

Acceleration in m/s^2 = 2/10 = 0.2 m/s^2

7 0

3 years ago

In preparation for an electrophoresis procedure, enzymes are added to DNA in order to

lapo4ka [179]

It is 2.) Cut the DNA into fragments

3 0

3 years ago