Answer:
C. 31.83 feet.
Step-by-step explanation:
We have been given that Trina has $1000 to purchase an open-top cylindrical dog pen in her backyard. She wants the height of the pen to be 5 feet.
First of all, we will find the surface area of dog pen using surface area of cylinder.
,where,
r = Radius of cylinder,
h = Height of cylinder.
Since the area of each square foot of pen costs $1, so in $1000 Trina can cover an area of 1000 square feet.
Now, we will set the surface area of cylinder equal to 1000 to solve for the radius.
Upon dividing both sides of our equation by 10 pi we will get,
Therefore, the radius of the dog pen is 31.83 feet and option C is the correct choice.
The fact that this triangle is a right angle triangle makes you now have 2 angles and the 1 side given, so it should be solvable.
First, You know that A=46 and C=90 as it is the right angle, and you know that the sum of any triangle's angles is 180. so now B=180-(90-46)=44
Now to the sides,
sin(B)=opp./hyp.=b/c=8/c=sin(44)
so, c=8/sin(44) which is approximately 11.52 unit length
now, use Pythagoras to find a,
a=√c²-b² =√11.52²-8² which is approximately 8.3 unit length.
Hope this helps.
Prob(spinning a number < 3on 1 spin) = Prob( spinning 1 or 2) = 2/5
Prob( spinning <3 3 times) = 2/5 * 2/5 * 2/5 = 8/125
These events are independent so we multiply the probabilities.
1,400 js the answer
I have it for a class
Explanation
Bababoey
From the box plot, it can be seen that for grade 7 students,
The least value is 72 and the highest value is 91. The lower and the upper quartiles are 78 and 88 respectively while the median is 84.
Thus, interquatile range of <span>the resting pulse rate of grade 7 students is upper quatile - lower quartle = 88 - 78 = 10
</span>Similarly, from the box plot, it can be seen that for grade 8 students,
The
least value is 76 and the highest value is 97. The lower and the upper
quartiles are 85 and 94 respectively while the median is 89.
Thus, interquatile range of the resting pulse rate of grade 8 students is upper quatile - lower quartle = 94 - 85 = 9
The difference of the medians <span>of the resting pulse rate of grade 7 students and grade 8 students is 89 - 84 = 5
Therefore, t</span><span>he difference of the medians is about half of the interquartile range of either data set.</span>
