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anygoal [31]
2 years ago
15

Let f(x)=cos(x)x^-2 F’(x)=

Mathematics
1 answer:
kondaur [170]2 years ago
8 0

f(x)=cos(x)x^{-2}\implies f(x)=\cfrac{cos(x)}{x^2}\implies \cfrac{df}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{-sin(x)\cdot x^2-cos(x)\cdot 2x}{(x^2)^2}} \\\\\\ \cfrac{df}{dx}=\cfrac{-x[x\cdot sin(x)+2cos(x)]}{x^4}\implies \cfrac{df}{dx}=\cfrac{-[xsin(x)+2cos(x)]}{x^3}

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15) Option B. 3

16) Option H. 144

17) Option B. -21

18) Option H. a^4 + 2

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So, the 217th digit after the decimal point of 0.3456 is one of the 4n+1st digits (with n=54) and must be 3.

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17) when you solve the equation x^2 + 4x - 21 = 0 you get two solutions.

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Out of these factors that we get, (a^4 + 2) is the only polynomials listed in the answer choices.

19) 2n - 5 / n when n = 1/4

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