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leva [86]
3 years ago
11

3. Which part of Thomson's plum pudding model was different from Rutherford's model?

Chemistry
1 answer:
horsena [70]3 years ago
8 0

Answer:

The difference between the Thompson's plum pudding model and the Rutherford atom model is the location of the electrons (option a).

Explanation:

While Thompson compared his atom to a plum pudding, where the electrons floated freely in the pudding, Rutherford established the arrangement of the electrons in orbitals, which were found around the atomic nucleus like the planets around the sun.

Rutherford's findings also established the existence of a small, positively charged nucleus.

<em>Thompson and Rutherford models did not differentiate between the charges of electrons and protons , overall charges or overall size of the atom.</em>

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What is landform? please help
KATRIN_1 [288]

Answer:

A landform is a natural or artificial feature of the solid surface of the Earth or other planetary body.

Explanation:

For example, valleys, plateaus, mountains, plains, hills etc.

3 0
3 years ago
Read 2 more answers
What volume of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to wate
8_murik_8 [283]

Answer:

200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water.

Explanation:

The solution is the result of the mixture between the solute, which is the substance that dissolves, and the solvent, which is the substance in which a solute dissolves. That is, a solution (or solution) is a mixture of two or more components, perfectly homogeneous since each component is intimately mixed with the other.

The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. A unit of concentration is the percent weight to volume.

The percent weight to volume is the percentage ratio between the weight of the solute and the volume of the solution. It is calculated as:

Percent =\frac{mass of solute}{volume of solution} *100

Mass is measured in grams, while volume is measured in mL.

In this case:

  • Percent weight to volume= 6%
  • mass of solute= 12 g
  • volue of solution= ?

Replacing:

6=\frac{12 g}{volume of solution} *100

Solving:

volume of solution*6= 12 g*100

volume of solution=\frac{12 g}{6} *100

volume of solution= 200 mL

<u><em>200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water</em></u>

<u><em> </em></u>

<u><em></em></u>

8 0
3 years ago
What is the electron configuration for nickel (Ni)?
solmaris [256]
It’s

1s2 2s2 2p6 3s2 3p6 4s2 3d6
5 0
3 years ago
Read 2 more answers
Which one of the following chemical equations is balanced? A. 2NaCl + H2SO4 → HCL + NaSO4 B. 2Na + S → 2NaS C. KOH + H2SO4 → KHS
Molodets [167]
To determine whether our equations are balanced, we must write the elements on the products side and also the reactants side. If the amount of the elements (coefficients and subscripts) are equal on both sides, we have a balanced equation. 

Lets try (A)

2NaCl + H₂SO₄ → HCl + NaSO₄

Na=2                    Na=1
Cl=2                    Cl=1
H=2                      H=1
Na=2                    Na=1
S=1                      S=1
O=4                     O=4
Most of the elements here are not equal for both sides, therefore, A is not the answer. 

Lets try (B)
2Na + S → 2NaS

Na=2        Na=2
S=1          S=2
This is a wrong answer because S is not equal on both sides. B is a wrong answer. 

Lets try (C)
KOH + H2SO4 → KHSO4 + H2O

K=1                       K=1                  
O= 1                     O=1
H=1                      H=1
H=2                     H=2
S=1                      S=1 
O=4                     O=4

THIS IS A BALANCED EQUATION!!!! ALL ELEMENTS ARE EQUAL ON BOTH SIDES!!!

Since we already know that C is our answer, we have no need to check D. Also, D is incorrect because N has 1 on reactants side, and 2 on the other. Therefore, we automatically know that D is wrong.

FINAL ANSWER: C IS OUR ANSWER, IT IS A BALANCED EQUATION. :)

 




3 0
3 years ago
Read 2 more answers
if there are 19 grams of oxygen in a sample of aluminum oxide . how many grams of aluminium are present ​
Maksim231197 [3]

Explanation:

Al2O3

16=molar mass of one oxygen atom

Number of moles: mass/molar mass

Mol of O3: 19÷(16*3) = 0.40 g/mol

mole ratio

0.40: 3 (oxygen)

0.27: 2 (aluminum)

Mass = molar mass*mole

0.27*(27*3)= 21.87g

3 0
3 years ago
Read 2 more answers
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