The atomic number increases moving left to right across a period and subsequently so does the effective nuclear charge. Therefore, moving left to right across a period the nucleus has a greater pull on the outer electrons and the atomic radii decreases.
Bonds payable to whomever holds them are called bearer bonds or unregistered bonds.
<h3>What is bearer bond ?</h3>
Bonds that have no registered owners are known as bearer bonds. Instead, the bond is owned by whoever "bears" (or has possession of) it. Bearer bonds, sometimes known as coupons, have coupons that bondholders can detach and present to receive interest payments.
<h3>What are interest payments ?</h3>
An interest rate is the amount of interest that is payable each period stated as a percentage of the amount that was lent, deposited, or borrowed. The principal amount, interest rate, frequency of compounding, and duration of the loan, deposit, or borrowing determine the total amount of interest on a sum that was lent or borrowed.
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:<span> </span><span>4 HCl + MnO2 → MnCl2 + 2 H2O + Cl2
(33.7 g MnO2) / (86.93691 g MnO2/mol) = 0.38764 mol MnO2
(45.3 g HCl) / (36.4611 g HCl/mol) = 1.2424 mol HCl
(a)
1.2424 moles of HCl would react completely with 1.2424 x (1/4) = 0.3106 mole of MnO2, but there is more MnO2 present than that, so MnO2 is in excess and HCl is the limiting reactant.
(b)
(1.2424 mol HCl) x (1 mol Cl2 / 4 mol HCl) x (70.9064 g Cl2/mol) = 22.0 g Cl2
(c)
(77.7% of 22.0 g Cl2) = 17.1 g Cl2</span>
Answer:
see explanation
Explanation:
Solutions are prepared from one of three solute sources ...
- solid solute from manufacturer,
-liquid solute from manufacturer,
-stock concentrate of solute for dilution to lower concentrations.
In this problem, sucrose is a stock solid with a formula mass of 342.3 grams/mol. The amount of solid needed can be determined using the formula:
mass of solute needed (grams) = (Molarity needed x Volume needed in Liters x formula weight) / (decimal fraction purity of stock solid)
Molarity needed = 0.3M
Volume needed = 500 ml = 0.500 liters
Formula weight = 342.3 grams/mole
Purity factor (assumed) = 100% = 1.00 (should be posted on stock bottle label) For example, a 95% pure stock solid => purity factor of 0.95.
∴ grams of sucrose needed = (0.3M*)(0.500L)(342.3g/mole)/(1.00) =51.345 grams sucrose.
Measure 51.345 grams of sucrose into mixing vessel and add solvent water up to, but not to exceed 500 ml total volume. Mix until homogeneous.