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Kryger [21]
3 years ago
14

the sum of three numbers is 11. if you triple the second number and add the third number, the result will be equal to the first

number. the first number is two times the second number. what are the numbers? 1st number = 9, 2nd number = 6, 3rd number = -4 1st number = 10, 2nd number = 5, 3rd number = 4 1st number = 10, 2nd number = 5, 3rd number = 14 1st number = 11, 2nd number = 5.5, 3rd number = -5.5
Mathematics
1 answer:
leonid [27]3 years ago
3 0
<span>1st number = 11, 2nd number = 5.5, 3rd number = -5.5</span>
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The effect of a monetary incentive on performance on a cognitive task was investigated. The researcher predicted that greater mo
riadik2000 [5.3K]

Answer:

1) H_0:\mu_5=\mu_{25}=\mu_{50}

2) H_a:\mu_{50}>\mu_{25}>\mu_{5}

3) A Type I error happens when we reject a null hypothesis that is true. In this case, that would mean that the conclusion is that there is evidence to support the claim that the greater the incentive, the more puzzles are solved, but that in reality there is no significant difference.

4) A Type II error happens when a false null hypothesis is failed to be rejected. In this case, that would mean that there is no enough evidence to support the claim that the greater the incentive, the more puzzles are solved, but in fact this is true.

5) The probability of a Type I error is equal to the significance level, as this is the chance of having a sample result that will make the null hypothesis be rejected.

Step-by-step explanation:

As the claim is that the greater the incentive, the more puzzles were solved, the null hypothesis will state that this claim is not true. That is that there is no significant relation between the incentive and the amount of puzzles that are solved. In other words, the mean amount of puzzles solved for the different incentives is equal (or not significantly different):

H_0:\mu_5=\mu_{25}=\mu_{50}

The research (or alternative hypothesis) is that the greater the incentive, the more puzzles were solved. That means that the mean puzzles solved for an incentive of 50 cents is significantly higher than the mean mean puzzles solved for an incentive of 25 cents and this is significantly higher than the mean puzzles solved for an incentive of 5 cents.

H_a:\mu_{50}>\mu_{25}>\mu_{5}

A Type I error happens when we reject a null hypothesis that is true. In this case, that would mean that the conclusion is that there is evidence to support the claim that the greater the incentive, the more puzzles are solved, but that in reality there is no significant difference.

A Type II error happens when a false null hypothesis is failed to be rejected. In this case, that would mean that there is no enough evidence to support the claim that the greater the incentive, the more puzzles are solved, but in fact this is true.

The probability of a Type I error is equal to the significance level, as this is the chance of having a sample result that will make the null hypothesis be rejected.

4 0
3 years ago
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qaws [65]

Answer:

y=1    x=1

Step-by-step explanation:

2x + y = 3

x = 2y - 1  

.

It looks like I could substitute the x=2y-1. Into 2x+y=3

2(2y-1)+y=3

4y-2+y=3

5y=5

y=1

x=2(1)-1

x=1

4 0
3 years ago
Subject Algebra 1
Mashutka [201]

Answer:

10x^{2}-34

Step-by-step explanation:

Because we are told equivalent expressions for y and z we can plug those in to 2(y+z).

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Then simplify by combining like terms of the expressions. Values ending in x^2 can be combined with each other.

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Now we can distribute the 2 by multiplying each value in the parentheses by 2.

10x^{2}-34

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The answer is B.
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Answer:

A

Step-by-step explanation:

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