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Eva8 [605]
3 years ago
5

Is the vertex maximum or a minimum​

Mathematics
2 answers:
Valentin [98]3 years ago
6 0

Step-by-step explanation:

In this case the vertex is a maximum since it's in the shape of a hill not a valley. Vertex is (0,4)

Vika [28.1K]3 years ago
5 0

Answer:

Maximum

Step-by-step explanation:

It is the maximum of the graph because it is the highest (MAXIMUM) point on the graph that the line reaches. If it were upside down, and the vertex was at the bottom and was the lowest point of the line, then it would be the minimum.

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The velocity v of an object rolled down an inclined plane is given by the formula v=39d where d is the distance the object has r
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V = 39d

Make d the subject

d = v/39
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3 years ago
If 7x+3=24 what is the value of 5-4x?
sleet_krkn [62]
If 7x+3=24, that means x would be 3 so if you take 5-4x then that would be -7.
5 0
4 years ago
Read 2 more answers
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
Leya [2.2K]

If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

⇒ 1 mL of IV will contain 60 / 1000 meq of kcal

As per the question,

The amount of IV infused in the patient = 400 mL

⇒ The amount of IV received by the patient in meq of kcal = 400 × (60 / 1000)

= 4 × 6

= 24 meq of kcal

Hence, the patient receives 24meq of kcal amount of IV.

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brainly.com/question/4567186

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6 0
2 years ago
Does anyone know how to solve this?
Oksi-84 [34.3K]

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3 0
2 years ago
Consider the sequence Two-fourths, three-fifths, four-sixths, StartFraction 5 Over 7 EndFraction, ellipsis Which statement descr
Phoenix [80]

Answer:

The sequence converges to 1

Step-by-step explanation:

Given

\frac{2}{4}. \frac{3}{5}, \frac{4}{6}, \frac{5}{7},...

Require

Description of the sequence

The given sequence follows:

\frac{2}{4}. \frac{3}{5}, \frac{4}{6}, \frac{5}{7},... \frac{n+1}{n+3}

i.e.

T_n = \frac{n+1}{n+3}

For every term,

\frac{n+1}{n+3} < 1

In other words,

as the value of n increases, \frac{n+1}{n+3} approaches 1

<em>Hence, (c) is true</em>

6 0
3 years ago
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