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Over [174]
3 years ago
13

Please help me with this question image attached

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
Hi there!

First, the area cannot be 15×8, or 120 cm^2, because this isn't a normal rectangle.

We can get our answer to what the length of the odd-looking lines are by seeing that the length of the top line of the cutout is equal to half of the 8 cm^2 line. Half of eight is four, so each line in the square cutout is a length of four.

So, our diameter is 15+8+8+4+4+4+4+4, or 52 cm^2.

Here is where even I'm getting stumped!

I think the answer is 100, because if you subtract 15×8=120 and subtract 4 (the length of the small sides) × 5 (the amount of them) you get 100 cm^2.

Try it, and see if it works!

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)
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Answer:

  A: -1, 3/5

  B: (-1/5, -3 1/5)

  2: plot the given points and draw a curve through them.

Step-by-step explanation:

<h3>Part A</h3>

The x-intercepts are most easily found from a graph of the function. I like the Desmos graphing calculator for this purpose. The x-intercepts are -1 and 3/5.

You can also find the x-intercepts by factoring the function.

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The x-intercepts are the values of x that make the factors zero:

  5x -3 = 0   ⇒   x = 3/5

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__

<h3>Part B</h3>

The vertex is on the axis of symmetry, which is the vertical line at the value of x halfway between the zeros. (-1 +3/5)/2 = (-2/5)/2 = -1/5

The value of f(x) there is ...

  f(-1/5) = (5(-1/5) +2)(-1/5) -3 = (-1 +2)(-1/5) -3 = -1/5 -3 = -3 1/5

The vertex is (-1/5, -3 1/5).

__

<h3>Part 2</h3>

The easiest step to take to graph the function is to type it into a graphing calculator (see attached).

If you're graphing this by hand, the three points given in parts A and B will be on the graph. The leading coefficient in the function is 3, so the x^2 parent function is vertically stretched by a factor of 3. This can make it a little more difficult to find points that lie on the graph.

Recognizing that the vertex form equation is ...

  f(x) = 3(x +1/5) -3 1/5

I might choose x-values that are -1/5 ± 1/2 to get y-values that are -3 1/5 + 3/4. And, x = -1/5 ± 1 ⇒ y = -3 1/5 +3.

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