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2 years ago

Please help me with this question image attached

Mathematics

1 answer:

Deffense [45]2 years ago

7 0

Hi there!

First, the area cannot be 15×8, or 120 cm^2, because this isn't a normal rectangle.

We can get our answer to what the length of the odd-looking lines are by seeing that the length of the top line of the cutout is equal to half of the 8 cm^2 line. Half of eight is four, so each line in the square cutout is a length of four.

So, our diameter is 15+8+8+4+4+4+4+4, or 52 cm^2.

Here is where even I'm getting stumped!

I think the answer is 100, because if you subtract 15×8=120 and subtract 4 (the length of the small sides) × 5 (the amount of them) you get 100 cm^2.

Try it, and see if it works!

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

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Step-by-step explanation:

For the answer you need to know bout equivalent fractions

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$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

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$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

Simplify,

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$

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$\frac{5(+-)\sqrt{17}}{4}$

Rewrite,

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