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sergij07 [2.7K]
3 years ago
9

An above-ground swimming pool in the shape of a cylinder has a diameter of 18 feet and a height of 4.5 feet.If the pool is fille

d with water to 6 inches from the top of the pool, what is the volume to the nearest cubic foot or their water in the pool
Mathematics
1 answer:
Furkat [3]3 years ago
3 0

Answer:

The volume of the water in the pool is 1,017 cubic feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=18/2=9\ ft ----> the radius is half the diameter

Remember that

1\ ft=12\ in

so

6\ in=6/12=0.5\ ft

To find out the height of the water, subtract 0.5 feet from the height of the swimming pool

h=4.5-0.5=4\ ft

assume

\pi =3.14

Find the volume of the water

V=(3.14)(9^{2})(4)

V=1,017\ ft^3

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A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s
Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

h(t)=-16t^2+32t+128

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

-16t^2+32t+128=0

The above is a quadratic equation. It can be solved by the formula as follows :

t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

Here, a = -16, b = 32 and c = 128

t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s

Neglecting negative value, the projectile will land after 4 seconds.

4 0
3 years ago
If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]?
kap26 [50]
<span>If f(x) = 2x + 3 and g(x) = (x - 3)/2, what is the value of f[g(-5)]? f[g(-5)] means substitute -5 for x in the right side of g(x), simplify, then substitute what you get for x in the right side of f(x), then simplify. It's a "double substitution". To find f[g(-5)], work it from the inside out. In f[g(-5)], do only the inside part first. In this case the inside part if the red part g(-5) g(-5) means to substitute -5 for x in g(x) = (x - 3)/2 So we take out the x's and we have g( ) = ( - 3)/2 Now we put -5's where we took out the x's, and we now have g(-5) = (-5 - 3)/2 Then we simplify: g(-5) = (-8)/2 g(-5) = -4 Now we have the g(-5)] f[g(-5)] means to substitute g(-5) for x in f[x] = 2x + 3 So we take out the x's and we have f[ ] = 2[ ] + 3 Now we put g(-5)'s where we took out the x's, and we now have f[g(-5)] = 2[g(-5)] + 3 But we have now found that g(-5) = -4, we can put that in place of the g(-5)'s and we get f[g(-5)] = f[-4] But then f(-4) means to substitute -4 for x in f(x) = 2x + 3 so f(-4) = 2(-4) + 3 then we simplify f(-4) = -8 + 3 f(-4) = -5 So f[g(-5)] = f(-4) = -5</span>
3 0
3 years ago
Which represents the reference angle for 3pi/4?
inn [45]

Answer:

(c) Pi/4

Step-by-step explanation:

3pi/4 = (3 x 180) / 4 = 135 degrees

135 degrees is equivalent to (180 degrees - 135 degrees) 45 degrees

45 degrees = Pi/4

Therefore, the reference angle of 3pi/4 is Pi/4

Thus, the correct option is (c) Pi/4

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3 years ago
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Natali [406]

Answer:

\huge\boxed{slope=-\dfrac{1}{3}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute the coordinates of the given points (-1, -1) and (2, -2):

m=\dfrac{-2-(-1)}{2-(-1)}=\dfrac{-2+1}{2+1}=\dfrac{-1}{3}=-\dfrac{1}{3}

5 0
3 years ago
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solniwko [45]

Answer:

B

Step-by-step explanation:

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