Answer:
Mass percent of food dyes = 0.0616%
Explanation:
Given data:
Mass of candy = 47.9 g
Calories = 240
Mass of fat = 10 g
Mass of carbohydrate = 34 g
Mass of protein = 2 g
Mass of food dyes = 29.5 mg
Mass percent of food dyes = ?
Solution:
First of all we will convert the mg into g.
Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g
Mass percent of food dyes = mass of food dyes / total mass× 100
Now we will put the values.
Mass percent of food dyes = 0.0295 g / 47.9 g × 100
Mass percent of food dyes = 0.000616 × 100
Mass percent of food dyes = 0.0616%
Answer:
Most metals have <u>luster</u> which means they <u>reflect</u> light
Explanation:
When light, which is made up of energetic photons, comes in contact with the surface of a metal, it is absorbed due to the corresponding energy gaps present between the metal orbital. The absorbed photons results in the raising of the energy levels of electrons within an atom of the metal which later drop back to a lower energy level and re-emit the photons which can now be observed as the metallic luster.
Hey there!
NaHCO₃
Notice that there is no subscript under Na.
That means there is one atom of Na for each molecule of NaHCO₃.
Hope this helps!
0.05M is the concentration of the solution.
The amount of a chemical substance in a mixture is expressed by the substance's concentration. Concentration can be expressed in numerous ways. In chemistry, the terms "solvent" and "solute" are used to denote the substance of interest and the medium in which it is dissolved, respectively
Subtract the solute's mass from the total volume of the solution. Using m as the solute's mass and V as the total volume of the solution, write out the equation C = m/V. To get the concentration of your solution, divide the mass and volume figures you discovered and plug them in.
C = m / V
C = 10 / 200
C = 0.05M.
Learn more about concentration here:
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If you are given the number of
moles of sodium bicarbonate, use the balanced chemical equation. The molar mass
of the acetic acid is 60 grams per mole. Using stochiometric balance.
Number of moles of acetic acid =
3 moles NaHCO3 (1 mol CH3COOH/1 mol NaHCO3) = 3 moles of acetic acid
Grams of acetic acid = 3 moles
of CH3COOH (60 g CH3COOH/1 mol CH3COOH) = <span>180 grams of acetic acid</span>
