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docker41 [41]
3 years ago
9

Fill in the blanks: Most metals have

Chemistry
1 answer:
victus00 [196]3 years ago
4 0

Answer:

Most metals have <u>luster</u> which means they <u>reflect</u> light

Explanation:

When light, which is made up of energetic photons, comes in contact with the surface of a metal, it is absorbed due to the corresponding energy gaps present between the metal orbital. The absorbed photons results in the raising of the energy levels of electrons within an atom of the metal which later drop back to a lower energy level and re-emit the photons which can now be observed as the metallic luster.

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Letter D is the answer

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You are given a solid that is a mixture of na2so4 and k2so4.
Murljashka [212]

Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

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Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

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When ironing clothes the primary method of heat transfers conduction convection insulation or radiation
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Based on the relative energy of the absorbed electromagnetic radiation, which absorber, a peptide bond or an aromatic side chain
alina1380 [7]

Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.

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  • When our energy is as low as possible, we are in the ground state.
  • What I want to point out is that if we can choose between the two options—peptide bond or aromatic side chain—without knowing the specific reasons, we can immediately rule out two potential answers.
  • Consider what we already know about energy, we have:

                                 E = h x c/λ

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Thus, Aromatic side chain exhibits an electronic excited state that is closer in energy to the ground state.

To view similar questions about energy, refer to:

brainly.com/question/14483627

#SPJ4

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2 years ago
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