Answer:
a) T = (2,375 ± 0.008) s
, b) When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
a) The period of a simple pendulum is
T = 2π √ L / g
Let's calculate
T = 2π √1.40 / 9.8
T = 2.3748 s
The uncertainty of the period is
ΔT = dT / dL ΔL
ΔT = 2π ½ √g/L 1/g ΔL
ΔT = π/g √g/L ΔL
ΔT = π/9.8 √9.8/1.4 0.01
ΔT = 0.008 s
The result for the period is
T = (2,375 ± 0.008) s
b) the experimental measure was T = 2.39 s ± 0.01 s
The theoretical value is comprised in a range of [2,367, 2,387] when we approximate this measure according to the significant figures the interval remains [2,37, 2,39].
When comparing this interval with the experimental value we see that it is within the possible theoretical values.
Explanation:
due to its shape st the bottom
Momentum = Mass × Velocity
= 61 × 8
= 488 kg m/s east
= 500 kg m/s east
Momentum is a vector quantity which means it has a direction as well as a numerical value (fancy word for this is magnitude). This means the final answer should also be in the direction "east".
Furthermore due to the significant figures in the question, the final answer should also be given to 1 sig fig (500) but if you don't want to then I imagine 488 is acceptable. (It's like this because we don't know how accurate we can be with the final answer from the numbers in the question.)
