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Katyanochek1 [597]

4 years ago

11

A sound wave can be considered as a displacement wave or a pressure wave? What phase difference exists between the displacement

and the pressure of a sound wave?

1 answer:

netineya [11]4 years ago

3 0

Where the displacement is a maximum the pressure is a minimum.
Where the displacement is zero, the pressure is a maximum.

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Water has a density of 1g/cm. An object displaces 40ml of water (1ml= 1 cm^3)

vazorg [7]

Mass=density*volume
1*40=40g/0.04kg

3 0

4 years ago

Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho

antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

$I = I_0 cos^2(\theta)$

$I_0 =$ Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

$\theta$ = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

$I_2 = I_0cos^2(45)$

For the third polarizer then we have,

$I_3 = I_2 cos^{2}(45)$

Replacing with the first equation,

$I_3 = I_0cos^2(45)cos^{2}(45)$

$I_3 = I_0 (\frac{1}{2})(\frac{1}{2})$

$I_3 = I_0 \frac{1}{4}$

Therefore the transmitted intensity now is $\frac{1}{4}$ of the initial intensity.

5 0

4 years ago

I need to know what a-e is. Please and thank you!

beks73 [17]

The different types of energy transfers are convection, conduction, and radiation.
I'm not too sure on the second one but thermodynamics relates thermal energy, kinetic energy, and potential energy. I'm basing this on the formulas of the laws of thermodynamics, but it could also be temperature, heat, or work.

6 0

3 years ago

An aluminum sphere is 8.55 cm in diameter. What will be it's % change in volume if it is heated from 30 C to 155 C?

Ghella [55]

We know that

• The sphere diameter is 8.55 cm.

,

• The temperature change is from 30 C to 155 C.

First, we have to find the radius of the sphere. The radius is the half diameter.

$\begin{gathered} r=\frac{d}{2}=\frac{8.55\operatorname{cm}}{2} \\ r=4.275\operatorname{cm} \end{gathered}$

Now we have to find the volume of the sphere using the following formula.

$V=\frac{4}{3}\pi(r)^3$

Where r = 4.275 cm.

$\begin{gathered} V=\frac{4}{3}\pi(4.275\operatorname{cm})^3 \\ V\approx327.26(cm)^3 \end{gathered}$

Then, we use the following formula

$V_2-V_1=BV_0(T_2-T_1)$

Where the initial volume is 327.26 cubic cm, B is a constant about thermal expansion for aluminum, and we have to find the final volume to then calculate the percentage change.

$\begin{gathered} \Delta V=75\times10^{-6}\cdot327.26(155-30) \\ \Delta V=75\times10^{-6}\cdot327.26(125) \\ \Delta V\approx3.07(cm)^3 \end{gathered}$

This means that the volume change is 3.07 cubic centimeters.

At last, we have to divide the volume change by the initial volume, and then we have to multiply it by 100% to express it as a percentage.

$\frac{\Delta V}{V_1}\times100=\frac{3.07}{327.26}\times100\approx0.938$ <h2>Therefore, the percentage change is 0.938%.</h2>

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1 year ago

Very Important!!

Murljashka [212]

Answer:

A. an alcohol - induced blackout

4 0

3 years ago

Read 2 more answers