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hichkok12 [17]
3 years ago
8

2. What is the least possible error encountered

Physics
2 answers:
Vlad1618 [11]3 years ago
8 0

Answer:

A because

Explanation:

because it has 1.0 mm

AlekseyPX3 years ago
6 0

Answer: b 0.5mm

Explanation:

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In the absence of air resistance, a ball of mass m is tossed upward to reach a height of 20 m. at the 10 m position, halfway up,
Mazyrski [523]

On the ball, there is mg of net force.

<h3>How would one describe air resistance?</h3>
  • Air exerts a force known as air resistance. The force works in the opposite direction of an object traveling through the air.
  • While a sports vehicle with a streamlined design will encounter reduced air resistance and experience less drag, the automobile will be able to move more quickly than a truck with a flat front.
<h3>What Causes Air Resistance?</h3>
  • Air resistance, also referred to as "drag," is a force brought on by air. When air specks collide with an object's front, it slows down.
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learn more about air resistance here

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5 0
2 years ago
Why might a scientist repeat an experiment if she did not make a mistake in the first one?
iren2701 [21]

Answer:

B

Explanation:

4 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 51.9 N . When the rock is totally i
Luden [163]

Answer:

\rho _{liquid}=1995.07kg/m^{3}

Explanation:

When the rock is immersed in unknown liquid the forces that act on it are shown as under

1) Tension T by the string

2) Weight W of the rock

3) Force of buoyancy due to displaced liquid B

For equilibrium we have T_{3}+B = W_{rock}

T_{3}+\rho _{Liquid}V_{rock}g=W_{rock}.....(\alpha)

When the rock is suspended in air for equilibrium we have

T_{1}=W_{rock}....(\beta)

When the rock is suspended in water for equilibrium we have

T_{2} + \rho _{water}V_{rock}g=W_{rock}.....(\gamma)

Using the given values of tension and solving α,β,γ simultaneously for \rho _{Liquid} we get

W_{rock}=51.9N\\31.6+1000\times V_{rock}\times g=51.9N\\\\11.4+\rho _{liquid}V_{rock}g=51.9N\\\\

Solving for density of liquid we get

\rho _{liquid}=\frac{51.9-11.4}{51.9-31.6}\times 1000

\rho _{liquid}=1995.07kg/m^{3}

5 0
3 years ago
Who thinks this a ufo? The following images are from a rare footage.
Galina-37 [17]

Answer:

That might be a sled ngl but it looks like a ufo but it's definitely not

5 0
3 years ago
Read 2 more answers
Can anyone help me with these questions ??
Helen [10]

1.u are given your formula as P=j over s

so ;1.2000 j over I = 2000w

      2.5000j over 5s = 1000w

      3.1,300j over 13s =100w

I aint so sure but u can take a shot..and please inbox me for futher details

3 0
3 years ago
Read 2 more answers
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