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3 years ago

A comparison often made between solids and

Chemistry

2 answers:

Mandarinka [93]3 years ago

7 0

The density of a plasma can be described as : ( A ) Low density

<h3><u>Density </u></h3>

Density is the mass per unit volume of a substance, it is used for comparison between substances because the mass and volume which are scalar quantities of substances are applied.

The density of plasmas are low when compared to solids because the volume occupied by a plasma of the same mass as a solid, is greater when compared to the volume occupied by a solid.

Hence we can conclude that The density of a plasma can be described as Low density.

Learn more about density : brainly.com/question/6838128

mojhsa [17]3 years ago

7 0

Answer:

the answer is A. low density

Explanation:

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tiny-mole [99]

Since there is loss of kinetic energy

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What is full ground state electron configuration of C-?

alexdok [17]

Answer:

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Explanation:

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3 years ago

A mysterious white powder could be powdered sugar (C12H22O11), cocaine (C17H21NO4), codeine (C18H21NO3), norfenefrine (C8H11NO2)

konstantin123 [22]

Answer: norfenefrine $(C_8H_{11}NO_2)$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-114.6-(-115.5)^0C=0.9^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $1.99^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (ethanol)= $density\times volume=0.789g/cm^3\times 1.50cm^3=1.18g=1.18\times 10^{-3}kg$

Molar mass of unknown non electrolyte = M g/mol

Mass of unknown non electrolyte added = 82 mg = 0.082 g (1g=1000mg)

$0.9=1\times 1.99\times \frac{0.082g}{M g/mol\times 1.18\times 10^{-3}}kg}$

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The molecular mass of norfenefrine $(C_8H_{11}NO_2)$ is near to 154 and thus the identity of the white powder is norfenefrine .

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3 years ago

A 5.00 g piece of metal is heated to 100.0 C then placed in a beaker containing 20.0 g of water at 10.0 C. The temperature of th

Nataly [62]

Calculate the heat gained by the water first.

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m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C

q = (20.0)(4.186)(5.0) = 419 J

This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)

q = mCpΔT —> Solve for Cp —> Cp = q/mΔT

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3 years ago

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Leto [7]

Answer:

I think it would be b. The octet rule states that transition metal group elements tend to react so that they attain a noble gas electron configuration.

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3 years ago