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2 years ago

A comparison often made between solids and

Chemistry

2 answers:

Mandarinka [93]2 years ago

7 0

The density of a plasma can be described as : ( A ) Low density

<h3><u>Density </u></h3>

Density is the mass per unit volume of a substance, it is used for comparison between substances because the mass and volume which are scalar quantities of substances are applied.

The density of plasmas are low when compared to solids because the volume occupied by a plasma of the same mass as a solid, is greater when compared to the volume occupied by a solid.

Hence we can conclude that The density of a plasma can be described as Low density.

Learn more about density : brainly.com/question/6838128

mojhsa [17]2 years ago

7 0

Answer:

the answer is A. low density

Explanation:

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

DENIUS [597]

Data:
$V_{initial} = 590\:mL$
$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → $T_{final} = 303.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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