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KengaRu [80]
3 years ago
9

In the equilibrium system below, which of the following changes would cause the equilibrium position to shift to the right? CO(g

) + 3H2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH4 (g) + H2O (g) delta H = -206 kJ/mol c
decreasing the concentration of carbon monoxide (CO)
increasing the volume of the reaction system
decreasing the concentration of hydrogen gas (H2)
lowering the temperature of the reaction
Chemistry
1 answer:
Lubov Fominskaja [6]3 years ago
4 0
<span>We are given with the equation that produces methane and water from the raection of hydrogen gas and carbon monoxide. This is expressed in the balanced equation: 3H2 + CO = CH4 + H2O. This is an exothermic process. The change that would shift the equilibrium to the right is </span><span>lowering the temperature of the reaction. </span>
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We can use this equation for boiling point elevation:
ΔT(b) = i K(b) M
when Δ T(b) is the increase of boiling point of the solution.
and i is ( vant Hoff factor, the number of particles or ions per mole-clue.
and K(b) is boiling point increase constant for the solution ( and for water it is equal 0.52 C° Kg/mol)
We can assume i (vant Hoff factor ) = 1 as the sucrose is nonelectrolyte (not readily ionize).
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By substitute at:
ΔTb = i Kb M
∴  = 1 * 0.52 * 3.60 = 1.8432 C°
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Hello,

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