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VARVARA [1.3K]
3 years ago
14

Give me the type of reactions ___ CuCO3 → ___ CuO + ___ CO2

Chemistry
2 answers:
Whitepunk [10]3 years ago
5 0
Decomposition reaction

When green copper carbonate{CuCO3} is heated it decomposes forming copper oxide {CuO} and carbon dioxide {CO2}. This is a decomposition reaction.
svetoff [14.1K]3 years ago
4 0
Decomposition because one compound breaks down two smaller parts
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Carl walked 12m north then turned around and walked back 4m south. What was his
aleksklad [387]

Answer:

Distance: 16m Displacement: 8m North

Explanation:

Total distance is the total amount traveled, regardless of direction. So, you would just add 12 and 4 to get a total distance of 16m. Displacement is the distance/direction from the start to the end point, regardless of which way you got there. So, to find displacement, you just subtract:

12m North - 4m South = 8m North

** I could be wrong so definitely double check this answer with a similar question**

3 0
3 years ago
one molecule of chlorophyll contains 137 atoms. how many of these atoms come from the metal magnesium?
Svetlanka [38]
The chemical formula for chlorophyll is C55H72O5N4<span>Mg. Only 1 of the 137 atoms comes from magnesium.

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7 0
3 years ago
A solution composed of 30.6g NH3 in 81.3g of H20. Calculate the mole fraction for NH3 and H20
irina [24]

Answer:

0.286 moles

Explanation:

i hope this is helpful for you

4 0
2 years ago
Read 2 more answers
PLEASE HELP ME ASAP URGENT IM STRESSED AND STUCK
Genrish500 [490]
Is there any more info lol
But from thinking I got A=DH^2*BC
8 0
3 years ago
1. An electric power plant uses energy from burning coal to generate steam at 450 °C. The plant is cooled by 20 °C water
kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is e=1-\frac{T_{2}}{T_{1}}

Here Temperature of hot source T_{1} = 450^{o}C=450+273=723 K

and Temperature of sink T_{1} = 20^{o}C=20+273=293 K

Hence the efficiency is  e=1-\frac{293}{723}=0.5947=59.47%

Now another formula for thermal efficiency Is

e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence Frome_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

W=e(Q_{1})=(0.5947)(100)=59.47MJ

Hence the of heat transferred to the river Is Q_{2} -W = (100 -59.47=40.53

6 0
3 years ago
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