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MArishka [77]
3 years ago
15

- When cabbage juice turns pink, that indicates that it is in the presence of a(n)

Chemistry
2 answers:
Bingel [31]3 years ago
5 0

Answer: an acid

Explanation:

Shtirlitz [24]3 years ago
3 0

Answer:

acid

Explanation:

im pretty sure because its then like a chemical reaction to the cabbage juice

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Elements on the current periodic table are organized by what ?
jasenka [17]

Answer:

atomic number

Explanation:

i'm assuming ur in eighth grade, bc same anyway good luck.

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The gravitational force acting on an object is also called the object's _____. A) mass B) weight C) density D) volume​
Veseljchak [2.6K]

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B) weight

Thats it no explanation

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4 years ago
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Yes carbohydrates have both monomers and polymers. Monomers of carbohydrates are monosaccharides (mono- one; saccharide- sugar)
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Complete the equation below for the neutralization reaction by writing the formula ofeach product. 40) KOH(aq) HCl(aq)
Montano1993 [528]
Acid + base = water + salt

KOH + HCl = H₂<span>O + KCl

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6 0
3 years ago
At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N
zhenek [66]

Answer : The value of equilibrium constant (K) is, 5.71\times 10^4

Explanation :

First we have to calculate the concentration of N_2,O_2\text{ and }N_2O

\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M

and,

\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M

and,

\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

N_2(g)+O_2(g)\rightarrow 2N_2O(g)

The expression for equilibrium constant is:

K=\frac{[N_2O]^2}{[N_2][O_2]}

Now put all the given values in this expression, we get:

K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}

K=5.71\times 10^4

Thus, the value of equilibrium constant (K) is, 5.71\times 10^4

7 0
4 years ago
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