Answer:
a) qrxn = 1,337.6 J
b) ΔHrxn /mol = -5.35 kJ/mol
c) See explanation below
Explanation:
a) q rxn = mcΔT where m is the mass of water, c its specific heat capacity , and ΔT is the change in temperature.
m H₂O = (50.0 mL + 50.0 mL) 1.00 g/mL= 100 g
q rxn = 100 g x 4.18 J/gK x (28.2 -25.0) K = 1,337.6 J
b) ΔHrxn = - qrxn
mol HCl =( 50mL/1000mL/L )x 0.500 mol/L = 0.025 mol
ΔHrxn / mol = -1337.6 J/0.025 mol = -53,504.0 J = -5.35 kJ/mol
c) We just calculated the heat of neutralization per mol HCl, but thats not the whole story.
We have to ensure that if we increase the quantity of HCl ( 0.100 mol) we also increase the amount NaOH in the same proportion, i.e. 0.100, if not only 0.025 mol HCl will react liberating the same amount of heat calculated above.
Answer:
A
Explanation:
Quaternary structure of proteins is composed of two or more polypeptide chains. Insulin has two; one alpha and one beta chain. The two chains are joined together by disulfide bonds at two points (at cysteines). Other examples of quaternary proteins structures are DNA polymerase and hemoglobin.
both
they are both living organisms so they can both do things like respiration photosynthesis protein synthesis etc...
Answer:
<h2>The answer is 6 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
where
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>6 J</h3>
Hope this helps you
1) Compund Ir (x) O(y)
2) Mass of iridium = mass of crucible and iridium - mass of crucible = 39.52 g - 38.26 g = 1.26 g
3) Mass of iridium oxide = mass of crucible and iridium oxide - mass of crucible = 39.73g - 38.26g = 1.47g
4) Mass of oxygen = mass of iridum oxide - mass of iridium = 1.47g - 1.26g = 0.21g
5) Convert grams to moles
moles of iridium = mass of iridium / molar mass of iridium = 1.26 g / 192.17 g/mol = 0.00656 moles
moles of oxygen = mass of oxygen / molar mass of oxygen = 0.21 g / 15.999 g/mol = 0.0131
6) Find the proportion of moles
Divide by the least of the number of moles, i.e. 0.00656
Ir: 0.00656 / 0.00656 = 1
O: 0.0131 / 0.00656 = 2
=> Empirical formula = Ir O2 (where 2 is the superscript for O)
Answer: Ir O2