MFe: 56 g/mol
..........
56g ----- 1 mol
5g ------- X
X = 5/56 = 0,089 moles of Fe
56g ----- 6,02×10²³ atoms
5g ------- X
X = (5×6,02×10²³)/56
X = 0,5375×10²³ = 5,375×10²² atoms of Fe
:•)
First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag
Metals usually melt when forming iron
Ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding
Answer:
more electron deficient
Explanation:
The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.
This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.
Hence, the nitro group makes the pyrinde ring more electron deficient
