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notsponge [240]
3 years ago
6

Choose the FALSE statement.

Chemistry
1 answer:
Mariana [72]3 years ago
5 0

Answer:

C. The half-life of C-14 is about 40,000 years.

Explanation:

The only false statement from the options is that the half-life of C-14 is 40,000yrs.

The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.

  • All living organisms contain both stable C-12 and the unstable isotope of C-14
  • The lower the C-14 compared to the C-12 ratio in an organism, the older it is.
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Read 2 more answers
"the charcoal from a tree killed in the volcanic eruption that formed cedar lake in oregon contained 44.5% of the carbon-14 foun
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The half life of carbon-14 is 5700 years. (Half life is the time taken by a radioactive isotope to decay by half of its original mass). 
Let A₀ be the initial amount of carbon-14 that is found in living matter (t=0 years), to determine when there was 44.5% of A₀ left.
44.5 = 100 × (1/2)^n, where n is the number of half lives
0.5^n = 0.445
    n = log 0.445/log 0.5
    n = 1.168
But 1 half life is 5700 years
Therefore, the number of years will be 5700 × 1.168 = 6658.299725 years
≈ 6658.30 years

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