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3 years ago

Given the balanced equation representing a reaction:

1 answer:

7 0

4Al(s) + 3O2(g) --> 2Al2O3(s) This is the balanced.
From the equation:

4 moles of Al required 3 moles of O2 to produce 2 moles of Al2O3

3 moles of O2 reacted with 4 moles of Al to produce 2 moles of Al2O3
1 mole of O2 reacted with 4/3 moles of Al to produce 2/3 moles of Al2O3 (Divide by 3)
4.5 moles of O2 reacted with (4/3 *4.5) moles of Al to produce (2/3*4.5) moles of Al2O3

4.5 moles of O2 reacted with 6moles of Al to produce 3moles of Al2O3

(3) is the answer. 6 mol of Al.

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Balance the equation pls

mihalych1998 [28]

Answer:

copy and paste this equation into the website

Explanation:

https://en.intl.chemicalaid.com/tools/equationbalancer.php

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3 years ago

a solution must be at a higher temperature than a pure solvent to boil. what colligative property can be employed to achieve thi

Kazeer [188]

Boiling-point elavation.

6 0

3 years ago

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The half-life for the radioactive decay of C-14C-14 is 5730 years. You may want to reference (Pages 598 - 605) Section 14.5 whil

KIM [24]

<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 5730 years

Putting values in above equation, we get:

$k=\frac{0.693}{5730yrs}=1.21\times 10^{-4}yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $1.21\times 10^{-4}yr^{-1}$

t = time taken for decay process = ? yr

$[A_o]$ = initial amount of the sample = 100 grams

[A] = amount left after decay process = (100 - 25) = 75 grams

Putting values in above equation, we get:

$1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{75}\\\\t=2377.9yrs$

Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %

8 0

3 years ago

Calculate the pH of the resulting solution if 26.0 mL of 0.260 M HCl(aq) is added to:

enyata [817]

So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
A. The result is pH= 14-pOH
B. There are 10ml of 0.26m HCL excees in this reaction so the answer is log(H)+

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3 years ago

Using water to measure the volume of small irregular shaped objects is called? *

Fed [463]

Answer:

B. water displacement is used "graduated cylinder is filled with water (100 mL) and the object is then put inside. ... If the new water level is (120 mL) we now know that the object has a volume of 20 mL."

Explanation:

4 0

2 years ago

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