Given that the reactants are the very consituents (elements) of the final compound, the enthalpy change of this reaction is the same heat of formation, Hf.
That means that the enthalpy chage for the reaction is -296.8 kj/mol
Answer:
Pareto diagram or bar graph
Explanation:
Answer:
4.7 atm
Explanation:
From the question given above, the following data were obtained:
Total pressure (P) = 15.3 atm
Pressure of Helium, P(He) = 3.2 atm
Pressure of Oxygen, P(O) = 7.4 atm
Pressure of Argon, P(Ar) =?
The pressure of Argon, P(Ar) in the tank can be obtained as illustrated below:
P = P(He) + P(O) + P(Ar)
15.3 = 3.2 + 7.4 + P(Ar)
15.3 = 10.6 + P(Ar)
Collect like terms
15.3 – 10.6 = P(Ar)
4.7 = P(Ar)
P(Ar) = 4.7 atm
Therefore, the pressure of Argon, P(Ar) in the tank is 4.7 atm
Hi! Well the formula of kinetic energy is Ke = 0.5 x M x V^2
0.5 x 0.5 x 10^2
0.25 x 20
5 J (joule)
