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3 years ago

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If the heat capacity of a 10 gram object is 300 J/C, the heat capacity of a 100 gram object of the exact same substance would be

equal to:
A. 300. J/C

B. 30,000. J/C

C. 3,000. J/C

D. 3.00 J/C

E. 30.0 J/C

1 answer:

I am Lyosha [343]3 years ago

3 0

Answer:

the answer should be see

that is 3000.J/C

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Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?

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Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.30 atm

$P_2$ = final pressure of gas = 5.40 atm

$V_1$ = initial volume of gas = 20.0 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = 308 K

$T_2$ = final temperature of gas = 416 K

Now put all the given values in the above equation, we get:

$\frac{2.30atm\times 20.0L}{308K}=\frac{5.40atm\times V_2}{416K}$

$V_2=11.5L$

Therefore, the final volume of gas is, 11.5 L

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In which of these diatomic molecules would you NOT find an octet of electrons

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Answer:

The hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

Explanation:

Let's evaluate each case.

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With Z = 7, nitrogen has the following electronic configuration

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Since its valence electrons are 5, in the molecule one nitrogen atom shares 3 electrons with the other one, and each remains with an electron pair, so <u>each atom has an octet of electrons.</u>

2. Hydrogen (H₂):

With Z = 1, its electronic configuration is:

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In the molecule, the hydrogen atoms share the only electron they have, so they will have only 2 electrons around. In this diatomic molecule, <em><u>we can not find an octet.</u></em>

3. Oxygen (O₂):

Z = 8. Electronic configuration:

1s²

2s² 2p⁴ → valence electrons

In the diatomic molecule, each oxygen atom shares 2 electrons with the other one and remains with 2 pairs of electrons, therefore, <u>each oxygen atom has an octet</u>.

4. Fluorine (F₂)

Z = 9. Electronic configuration:

1s²

2s² 2p⁵ → valence electrons

In this molecule, each fluorine atom shares 1 electron with the other and remains with 3 pairs of electrons, hence, <u>each fluorine atom has an octet of electrons around</u>.

Finally, we can say that the hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

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