you have to show us the rest of it because we have no idea what your looking at. I'm sorry
Answer:

Explanation:
There are two heat transfers involved: the heat lost by the metal block and the heat gained by the water.
According to the Law of Conservation of Energy, energy can neither be destroyed nor created, so the sum of these terms must be zero.
Let the metal be Component 1 and the water be Component 2.
Data:
For the metal:

For the water:




10.3 is good the correct rounding of three sig figures
Answer:
C. because the 4s orbital is at a lower energy level
<span>write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
You are given everything needed to calculate
q=heat transfer=2.2*10^2,
H3PO4 moles= 1.5*10^-3,
NaOH moles=5.0*10^-3
equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first
Now plug in variables
DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,</span>