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sineoko [7]
3 years ago
6

What ismetal refinning​

Chemistry
1 answer:
nikklg [1K]3 years ago
7 0

Answer:

It is the way of cleaning of impurities present in metals

You might be interested in
What is the value of for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 kj/mol
sineoko [7]

The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium

<h3>What is an aqueous reaction in equilibrium?</h3>

When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.

δG = − R T ln

          R = universal gas constant 8.313

          δG= 20. 46 kj/mol

           T =  298 k or 24.4 in celcius.

substituting the value in the equation.

20. 46 kj/mol = 8.313 × 24.4 in celcius × K

K =  8.313 × 24.4 in celcius / 20. 46 kj/mo

k = 9.91 mol .

Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium

Learn more about the aqueous reaction in  equilibrium, here:

brainly.com/question/8983893

#SPJ4

5 0
2 years ago
In an experiment, two unknown compounds (one an ether and the other an amine) of equal molecular mass were dissolved in water. T
Fittoniya [83]

Answer:

It is an amine; it contains a nitrogen atom that will allow nitrogen-hydrogen bonds to form while in water.

Explanation:

The solubility of amines owes largely to the electronegativity difference between nitrogen and hydrogen. Remember that when hydrogen is bonded to highly electronegative element such as nitrogen, intermolecular hydrogen bonding is possible with water molecules. This explains the greater solubility of amines in water.

Ether molecules do have an oxygen atom, however, and engage in hydrogen bonding with water molecules to a lesser extent compared to amines.

Also, amines participate in some acid-base reactions that lead to the formation of diethylammonium hydroxide, an ion which leads to a greater solubility of amines compared to an ether.

Hence, compound A is an amine.

3 0
3 years ago
A company produces and tests a new mineral supplement designed to prevent the common
irga5000 [103]

A change which would remove the source of this error is to: Test a fourth group, in which participants do not receive the mineral supplements.

<h3>What is a scientific method?</h3>

A scientific method can be defined as the various techniques that are adopted to observe, investigate, examine and study a particular thing while giving explanations on the basis of the evidence, theory, proof, hypothesis, or factual information they derived from the research work.

In this scenario, a claim was made by the company its mineral supplements can effectively prevent common cold. However, this claim was disputed by a scientist because there exist an error in the group setup.

<h3>How to remove an error in science</h3>

For this investigation, an effective and efficient way to remove this source of error would be by testing a fourth group, in which the mineral supplements is not administered to any of the participants.

Read more on scientific method here: brainly.com/question/17216882

8 0
3 years ago
In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion
love history [14]
The balanced reaction would be:<span>

C12H22O11 + 12O2 = 12CO2 + 11H2O

We are given the amount of oxygen used in the combustion. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(250 L) / (0.08206 atm L/mol K ) 273 K
n= 11.16 mol O2

</span>11.16 mol O2<span> (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

V = nRT/P =</span>11.16 mol CO2<span> x 273 K x 0.08206 atm L/mol K / 1 atm
V=250 L</span>
7 0
4 years ago
Write a molecular equation for the precipitation reaction that occurs (if any) when each pair of aqueous solutions is mixed.
wolverine [178]

Answer:

a. K₂CO₃(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbCO₃(s)

b. Li₂SO₄(aq) + Pb(C₂H₃O₂)₂(aq) → 2Li(C₂H₃O₂) + PbSO₄(s)

c. Cu(NO₃)₂(aq) + MgS(aq) → Mg(NO₃)₂(aq) + CuS(s)

d. NO REACTION

Explanation:

For the reactions, the cation and the anion of the compounds will be replaced. The reaction will occur if at least one of the products is insoluble and will form a precipitated.

a. Potassium carbonate = K₂CO₃

Lead(II) nitrate = Pb(NO₃)₂

Products = KNO₃ and PbCO₃.

According to the solubility rules, all K⁺ ions are soluble, with no exceptions, so KNO₃ is soluble. All CO₃⁻² ions are insoluble, and Pb⁺² is not an exception, so PbCO₃ will be insoluble and will form a precipitated, so the reaction happen:

K₂CO₃(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbCO₃(s)

b. Lithium sulfate = Li₂SO₄

Lead(II) acetate = Pb(C₂H₃O₂)₂

Products = Li(C₂H₃O₂) and PbSO₄

All Li⁺ are solubles, without exceptions, so Li(C₂H₃O₂) is soluble, and all SO₄⁻² are soluble, but Pb⁺² is an exception, so PbSO₄ is insoluble and will form a precipitated, then the reaction happens:

Li₂SO₄(aq) + Pb(C₂H₃O₂)₂(aq) → 2Li(C₂H₃O₂) + PbSO₄(s)

c. Copper(II) nitrate = Cu(NO₃)₂

Magnesium sulfide = MgS

Products = CuS and Mg(NO₃)₂

All NO₃⁻ are soluble, with no exceptions, so Mg(NO₃)₂ is soluble, and all S⁺² are insoluble, and Cu⁺² is not an exception, so CuS is insoluble, and will form a precipitated, then the reaction happens:

Cu(NO₃)₂(aq) + MgS(aq) → Mg(NO₃)₂(aq) + CuS(s)

d. Strontium nitrate = Sr(NO₃)₂

Potassium iodi = KI

Products = K(NO₃)₂ and SrI₂

All K⁺ are soluble, with no exceptions, so K(NO₃)₂ is soluble, and all I⁻ are soluble, and Sr⁺² are not an exception, then SrI₂ is soluble. Therefore, no precipitated is formed and the reaction doesn't happen.

6 0
3 years ago
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