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4 years ago

Plss help asap :) (if your reading this I hope you have a great day!)

Mathematics

1 answer:

Alika [10]4 years ago

8 0

Neither.

Parallel lines have the same slope.
Perpendicular lines have negative reciprocal slopes.

Rewriting the 2nd equation to solve for y,
You get:

Y=1/5x + 1/2

The first equation slope is negative, and the second is positive. However, the second slope is 1/5, and not 5/1 - which would be the negative reciprocal of (-1/5)from the first equation.

Hope that helps!

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How does 1/12 - 5/6 = 9/12 um tring to learn how to add this like ?

tekilochka [14]

Answer:

see below

Step-by-step explanation:

1/12 - 5/6 = -9/12

We need to get a common denominator of 12

1/12 - 5/6*2/2 = -9 /12

1/12 - 10/12 = -9/12

Since the denominators are the same, we can subtract the numerators

1-10 = -9

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We can simplify -9/12 by dividing the top and bottom by 3

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3 years ago

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Kay [80]

Answer:

$\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=\dfrac{2}{\sqrt{3}}.$

Step-by-step explanation:

The given angle is 240 degrees.

We need to find the exact value of each trigonometric function for the given angle θ.

Since $\theta=240$ , it means θ lies in 3rd quadrant. In 3d quadrant only tan and cot are positive.

$\sin (240^\circ)=\sin (180^\circ+60^\circ)=-\sin (60^\circ)=-\dfrac{\sqrt{3}}{2}$

$\cos (240^\circ)=\cos (180^\circ+60^\circ)=-\cos (60^\circ)=-\dfrac{1}{2}$

$\tan (240^\circ)=\tan (180^\circ+60^\circ)=\tan (60^\circ)=\sqrt{3}$

$\cot (240^\circ)=\cot (180^\circ+60^\circ)=\cot (60^\circ)=\dfrac{1}{\sqrt{3}}$

$\sec (240^\circ)=\sec (180^\circ+60^\circ)=-\sec (60^\circ)=-2$

$\csc (240^\circ)=\csc (180^\circ+60^\circ)=-\csc (60^\circ)=-\dfrac{2}{\sqrt{3}}$

Therefore, $\sin (240^\circ)=-\dfrac{\sqrt{3}}{2},\cos (240^\circ)=-\dfrac{1}{2},\tan (240^\circ)=\sqrt{3},\cot (240^\circ)=\dfrac{1}{\sqrt{3}},\sec (240^\circ)=-2,\csc (240^\circ)=-\dfrac{2}{\sqrt{3}}.$

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Answer:

(6,9) nice

Step-by-step explanation:

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