In the given problem it is already stated that the cost of each eggs is 15 cent. Out the total eggs bought 6 were broken. The rest of the eggs were sold for 20 cents each and the profit made was $4.80.
Cost of the 6 broken eggs = (6 * 0.15)
= 0.9 cents
Let us assume that the number of eggs bought = x
Then we can write the equation as
0.2x - (0.15x - 0.9) = 4.80
0.2x - 0.15x + 0.9 = 4.80
0.05x = 4.80 - 0.9
0.05x = 3.9
x = 3.9/0.05
= 78
So the number of eggs bought by him is 78
C - 10 = g
L - 5 = C
g = 5
then altogether he finds
40 bugs
Answer:
O-2(x+5)
Step-by-step explanation:
I have to much time on my hands
Answer:
Samuel has $336 and Zander has $56
Step-by-step explanation:
Samuel = 6x because he has 6 times Zander
Zander = x
Together they have 392
6x + x = 392
7x = 392
Divide both sides by 7
x = 56
Samuel = 6 x 56 = 336
Zander = 56
336 + 56 = 392
9514 1404 393
Answer:
F20 = 15985k -20361g
Step-by-step explanation:
If we assume F3 and F4 are the third and fourth terms of an arithmetic sequence, the common difference is ...
d = F4 -F3 = (945k -713g) -(5k +515g)
d = 940k -1228g
Then the 20th term is ...
F20 = F3 +(20 -3)d = (5k +515g) +17(940k -1228g)
F20 = 15985k -20361g
