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Wewaii [24]
3 years ago
15

PLEASEEEE HELPPPPPPPPPPP

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

The correct option is first graph.

Therefore,

The two points for the line y+5=-2(x-4) ( red color )line are

point A( x₁ , y₁) ≡ ( 0 , 3)  .......Blue color

point B( x₂ , y₂) ≡ (\dfrac{3}{2},0)  ............Green color

The Graph is attached below.

Step-by-step explanation:

Given:

y+5=-2(x-4)

Which can also be written as

y=-2x+8-5\\y=-2x+3     .....Equation of line

Let the points be point A, and point B  

To Find:

point A( x₁ , y₁) ≡ ?

point B( x₂ , y₂) ≡ ?

Solution:

For Drawing a graph we require minimum two points but we will have here three points.

For point A( x₁ , y₁)

Put x = 0 in the given equation we get

y = -2 × 0 +3

y =3

∴ y = 3

∴ point A( x₁ , y₁) ≡ ( 0 , 3)

For point B( x₂ , y₂)

Put y = 0 in the given equation we get

0 = -2x + 3

x=\dfrac{3}{2}

∴ point B( x₂ , y₂)  ≡ (\dfrac{3}{2},0)

Therefore,

The two points for the line y+5=-2(x-4) ( red color )line are

point A( x₁ , y₁) ≡ ( 0 , 3)      .......Blue color

point B( x₂ , y₂) ≡ (\dfrac{3}{2},0)  ............Green color

The Graph is attached below.

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zimovet [89]

x=2+½*\sqrt{10}

or

x=2-½*\sqrt{10}

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

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by using quadratic equation

x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}

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taking positive

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x=2+½*\sqrt{10}

taking negative

x=2-½*\sqrt{10}

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3 years ago
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Answer:

C

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sertanlavr [38]

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Answer:

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