Question

What is the energy of light that must be absorbed by a hydrogen atom to transition an electron from n = 3 to n = 5?

Answer 1

Answer:

The energy absorbed by a hydrogen atom is 1.549 X10⁻¹⁹ J

Explanation:

Using Bohr's equation; the energy absorbed by the hydrogen atom can be calculated as follows:

$\delta E = (\frac{1}{n_2{^2}} -\frac{1}{n_1^{2}})13.6eV$

When an electron moves from a lower energy level to a higher energy level, energy is absorbed by the atom.

Lower energy level (n₂) = 3

Higher energy level (n₁) = 5

1 eV = 1.602X10⁻¹⁹ C

$\delta E = (\frac{1}{3{^2}} -\frac{1}{5^{2}})13.6X1.602X10^{-19}$

ΔE = 1.549 X10⁻¹⁹J

The energy absorbed by a hydrogen atom  to transition an electron from n = 3 to n = 5 is 1.549 X10⁻¹⁹ J