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eduard
3 years ago
8

Weight is used most often for measuring____________________ whereas volume is used most often for measuring_____________________

___
Physics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

Weight is used most often for measuring solid whereas volume is used most often for measuring liquid.

Explanation:

Weight is used most often for measuring solid, because solids have definite shape.  Weight is usually expressed in Newton (N) because it is a function of mass and gravity. ( weight = mass x gravity).

Whereas  volume is used most often for measuring liquid, usually expressed in cubic meter (m³) because liquids have no definite shape, rather they occupy the volume of their container.

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As shown in the diagram below, a rope attached to a 500.-kilogram crate is used to exert a force of 45 newtons at an angle of 65
kaheart [24]

Answer:

19.01 N

Explanation:

F = Force being applied to the crate = 45 N

\theta = Angle at which the force is being applied = 65^{\circ}

Horizontal component of force is given by

F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}

The horizontal component of the force acting on the crate is 19.01 N.

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3 years ago
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Explanation:

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Two points A=(+16) and B=(-4) At electric potential respectively find:
Damm [24]

Answer:

a. Point A

b. 20 V

c. 100 J

Explanation:

a. Point A is at a higher potential because there is a positive sign in front of its magnitude. Since it is a positive integral value, and has a higher magnitude than point B which is at -4, point A is thus at a higher potential than point B.

b. The potential difference between the two points ΔV = A - B

= +16 V - (-4 V)

= +16 V + 4 V

= + 20 V

c. The work done, W in moving a charge Q across a potential difference ΔV is W = QΔV

So, since Q = 5 C and ΔV = + 20 V  

W = QΔV

= 5 C × (+ 20 V)

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4 0
3 years ago
Calculate the mass of an object that is accelerating 14 m/s^2 with a force of 280 N
Masteriza [31]

Answer:

\boxed {\boxed {\sf 20 \ kilograms }}

Explanation:

Force is the product of mass and acceleration.

F=m*a

We can find mass, since we know the acceleration and force.

The acceleration is 14 meters per square second. The force is 280 Newtons, but we should convert the units to make the problem simpler later on.

  • 1 kilogram meter per square second is equal to 1 Newton.
  • 280 Newtons are equal to 280 kg*m/s²

F= 280 \ kg*m/s^2 \\a= 14 \ m/s^2

Substitute the values into the formula.

280 \ kg*m/s^2 = m* 14 \ m/s^2

We want to solve for the mass or m. Therefore we must isolate the variable on one side of the equation.

m is being multiplied by 14 m/s². The inverse of multiplication is division. Divide both sides of the equation by 14 m/s²

\frac{280 \ kg*m/s^2}{14 \ m/s^2}=\frac{m*14 \ m/s^2}{14 \ m/s^2}

\frac{280 \ kg*m/s^2}{14 \ m/s^2}=m

The m/s² will cancel, which is why we converted the units earlier.

\frac{280 \ kg}{14 }=m

20 \ kg=m

The mass of the object is <u>20 kilograms.</u>

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