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Oksanka [162]
3 years ago
15

Consider the quadratic equation ax^2+bc+c=0, where a, b, c are rational numbers and the quadratic has two distinct zeros. If one

zero is rational, which of the following is true of the other zero?
Mathematics
1 answer:
Katyanochek1 [597]3 years ago
4 0
With rational coefficients (a, b and c), if one zero is rational, that means the discriminant is rational.  We can conclude that the other is also rational.
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Set it up into ratio or proportion

8/50 :: x/60
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HELP I WILL MAEK BEAINLIST PLEASE
wolverine [178]

Answer:

260,548668 or 260.55 round to the nearest hundreds  

Step-by-step explanation:

Area of the trapezoid:

[(major base + minor base)x height]/2

[(22 + 12) x 12]/2 = 204 cm^2

radius = diameter / 2 = 12 / 2 = 6 cm

Area of a semicircle

(radius^2 x pi)/2 = (6^2 x pi)/2 = 56.548668 cm^2

total area = 204 + 56,548668 = 260,548668 cm^2

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3 years ago
Hana paid $1,200 for the carpet in her living room the carpet has area of 251.2 square feet what was her unit cost of carpeting
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The answer is $4.78 

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4 0
3 years ago
Absolute value for |27 1/4|
mr_godi [17]

Answer:

27 1/4

Step-by-step explanation:

4 0
3 years ago
Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe
valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0
2 years ago
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