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xz_007 [3.2K]
3 years ago
12

Find the slope of the line that passes through the points (0,-11) and (8,-8).

Mathematics
2 answers:
castortr0y [4]3 years ago
8 0

Answer:

Step-by-step explanation:

(x₁  ,y₁) = (0,-11)     & (x₂ , y₂) =   (8,-8)

Slope = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\

          =\dfrac{-8-[-11]}{8-0}\\\\=\dfrac{-8+11}{8}\\\\=\dfrac{3}{8}

Korolek [52]3 years ago
5 0

To find the slope of a line, we can use the following formula:

\displaystyle \large{m =  \frac{y_2 - y_1}{x_2 - x_1} }

m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:

\displaystyle \large{(x_1,y_1) = (0, - 11)} \\  \displaystyle \large{(x_2,y_2) = (8, - 8)}

Substitute the points in formula:

\displaystyle \large{m =  \frac{ - 8 -( - 11)}{ 8 - 0} }

Negative multiply negative always come out as positive.

\displaystyle \large{m =  \frac{ - 8  +  11}{ 8 - 0} } \\  \displaystyle \large{m =  \frac{ 3}{ 8 } } \\

Since m stands for slope, we can say that:

\displaystyle  \large \boxed{ \tt{slope  =  \frac{3}{8} }}

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