Question

Find the slope of the line that passes through the points (0,-11) and (8,-8).

Answer 1

Answer:

Step-by-step explanation:

(x₁  ,y₁) = (0,-11)     & (x₂ , y₂) =   (8,-8)

Slope = $\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

          $=\dfrac{-8-[-11]}{8-0}\\\\=\dfrac{-8+11}{8}\\\\=\dfrac{3}{8}$

Answer 2

To find the slope of a line, we can use the following formula:

$\displaystyle \large{m = \frac{y_2 - y_1}{x_2 - x_1} }$

m-term stands for slope or gradient. The formula is useful whenever you want to find a slope of two points.

Let these be the following:

$\displaystyle \large{(x_1,y_1) = (0, - 11)} \\ \displaystyle \large{(x_2,y_2) = (8, - 8)}$

Substitute the points in formula:

$\displaystyle \large{m = \frac{ - 8 -( - 11)}{ 8 - 0} }$

Negative multiply negative always come out as positive.

$\displaystyle \large{m = \frac{ - 8 + 11}{ 8 - 0} } \\ \displaystyle \large{m = \frac{ 3}{ 8 } }$

Since m stands for slope, we can say that:

$\displaystyle \large \boxed{ \tt{slope = \frac{3}{8} }}$