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worty [1.4K]
2 years ago
5

Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?

Chemistry
1 answer:
Sindrei [870]2 years ago
8 0
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂   = 4 x 1 / 2

= 2  moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x  2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!
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Find the percent composition of C7H5N3O6
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Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

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Add all of those pieces together.

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Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %

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You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

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