Answer:
0.54 mole of H2O.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2CH3OH + 3O2 —> 2CO2 + 4H2O
From the balanced equation above,
2 moles of CH3OH reacted to produce 4 moles of water.
Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:
From the balanced equation above,
2 moles of CH3OH reacted to produce 4 moles of water.
Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.
Thus, 0.54 mole of H2O is produced from the reaction.
The final volume of the unknown gas is 787.5 ml
Given:
volume of unknown gas = 450.0 mL
initial pressure of unknown gas = 0.07 atm
final pressure of unknown gas = 0.04 atm
To Find:
final volume of the unknown gas
Solution:
Substituting these values into Boyle’s law, we get
P1V1 = P2V2
(0.07)(450) = (0.04)V2
V2 = (0.07)(450)/(0.04)
V2 = 787.5
So, final volume of the unknown gas is 787.5 ml
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Answer:
0.49 mol
Explanation:
Step 1: Write the balanced equation
Mg + 2 HCI ⇒ MgCl₂ + H₂
Step 2: Calculate the moles corresponding to 12 g of Mg
The molar mass of Mg is 24.31 g/mol.

Step 3: Calculate the moles of H₂ produced by 0.49 moles of Mg
The molar ratio of Mg to H₂ is 1:1. The moles of H₂ produced are 1/1 × 0.49 mol = 0.49 mol.
Answer:
Ionic compound are when electrons are given to another element, making one atom positive and the other negative, so they attract. Covalent compound is when both atoms share electrons with each other.