Draw or sketch out any problems like this, otherwise they appear abstract.
A circle’s area can be calculated by (pi d^2)/4 We have an area of 56 cm (^2?), so
pi d^2 = 56 x 4 (or 224) d^2 = 224/pi, d = √(224/pi)
A circle circumscribed around a square has a diameter equivalent to the length of the square’s diagonal, so the square’s diagonal is √(224/pi) (same as the circle diameter…)
A square’s side can be calculated, knowing its diagonal length, by use of Pythagoras’ theorem… The diagonal √(224/pi) is squared, divided by two, since the square’s sides are all equal, and the resulting number’s square root is calculated.
Squaring √(224/pi), we get 224/pi, and dividing by two, we get 112/pi, which is 35.6507 (cm^2), and the square root is 5.9708 cm, the side of the square.
I cannot emphasize enough that a drawing or sketch is an invaluable tool for these tasks, it saves having to retain a “picture” in your head. Note that a calculator was not required up until the last moment, dividing 112 by pi, and finding the square root of that answer. Picking up the calculator too early obliges you to transcribe numbers from the calculator to paper, and that can lead to issues. Try to enjoy maths, see it as a challenge not a chore. (and use correct units!)
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Related Questions (More Answers Below)
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
5.73 so rounded up, it would be 6.
Answer:
x = 1 , y = 1 and z = 0
Step-by-step explanation:
-2x+2y+3z=0 ------(1)
-2x-y+z=-3 --------(2)
2x+3y+3z=5 ---------(3)
<u>To find the values of x,y and z</u>
(3) - (2)⇒ 2y + 4z = 2
y + 2z = 1 --------(4)
(1) - (2)⇒ 3y +2z =3 ---(5)
(5) - (4)⇒ 2y = 2
y = 1
Substituting the value of y in (4) we get z =0
Substituting the value of y and z in (1) we get x = 1
Therefore x = 1 , y = 1 and z = 0
Answer:
Rate of change of the area of the square is 42 units at t = 2.
Step-by-step explanation:
We note that the area of the square is given by: 
but we aim to find 
. But we can use the chain rule to pull out that dA/dt. Doing so gives us:
Now, 
(by the power rule and 
But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.
So, finally, we see that:
