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s2008m [1.1K]
2 years ago
15

Graph the inequality. 1

Mathematics
1 answer:
Mrrafil [7]2 years ago
6 0

Answer:

hope it helps

Step-by-step explanation:

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Roulette is a very popular game in many American casinos. In roulette, a ball spins on a circular wheel that is divided into 38
ludmilkaskok [199]

Answer:

a. P(AUB) = 0.74

b. P(A∩C) = 0.24

c. P(BUC) = 0.71

d. P(Bc) = 0.55

e. P(A∩B∩C) = 0.11

Step-by-step explanation:

n(U) = Total number of elements in the set = number of elements in the universal set = 38

A: (Outcome is an odd number (00 and 0 are considered neither odd nor even)]

An odd number referred to any integer, that is not a fraction, which is not possible to be divided exactly by 2. Therefore, we have:

A: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35

B: 2, 4, 6, 8, 10, 11, 13, 15, 17, 20, 22, 24, 26, 28, 29, 31, 33, 35

C: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18

a. Calculate the probability of AUB

AUB picks not more than one each of the elements in both A and B without repetition. Therefore, we have:

AUB = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 15, 17, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 31, 33, 35

n(AUB) = number of elements in AUB = 28

P(AUB) = probability of AUB = n(AUB) / n(U) = 28 / 38 = 0.736842105263158 = 0.74

b. Calculate the probability of A ∩ C  

A∩C picks only the elements that are common to both A and C. Therefore, we have:

A∩C: 1, 3, 5, 7, 9, 11, 13, 15, 17

n(A∩C) = number of elements in A∩C = 9

P(A∩C) = probability of A∩C = n(A∩C) / n(U) = 9 / 38 = 0.236842105263158 = 0.24

c. Calculate the probability of BUC

BUC picks not more than one each of the elements in both B and C without repetition. Therefore, we have:

BUC: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 20, 22, 24, 26, 28, 29, 31, 33, 35

n(BUC) = number of elements in BUC = 27

P(BUC) = probability of A∩C = n(BUC) / n(U) = 27 / 38 = 0.710526315789474 = 0.71

d. Calculate the probability of Bc

Bc indicates B component it represents all the elements in the universal set excluding the elements in B. Therefore, we have:

Bc: 00, 0, 1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36

n(Bc) = number of elements in Bc = 20

P(Bc) = probability of Bc = n(Bc) / n(U) = 20 / 38 = 0.526315789473684 = 0.55

e. Calculate the probability of A∩B∩C

A∩B∩C picks only the elements that are common to A, B and C. Therefore, we have:

A∩B∩C: 11, 13, 15, 17

n(Bc) = number of elements in A∩B∩C = 4

P(A∩B∩C) = probability of A∩B∩C = n(A∩B∩C) / n(U) = 4 / 38 = 0.105263157894737 = 0.11

Note: All the answers are rounded to 2 decimal places.

7 0
3 years ago
While attending a film festival you decide that there are 13 movies that you are interested in seeing. However, you only have ti
kifflom [539]
<span>A. 8,648,640
B. 13
C. 665,280
D. 4,324,320
</span>Assume you don't watch movies twice.
If you have 13 movies to pick from, then you have 13 choices for the first movie. Then, only 12 choices are left.  Do this until only 6 are left (13-7=6)
This equates to 13*12*11*10*9*8*7=8,648,640
Therefore, the answer is A, 8,648,640 different ways.

Hope this helps!
5 0
3 years ago
Read 2 more answers
Pls help PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLD
Firdavs [7]

Answer:

4a: 1

4b: 6, -6

Step-by-step explanation:

4a. (3 - 5)= -2; (9 - 6)=3

(-2 + 3) = 1

4b. We aren't told which cards Jesse pick up, only that they didn't affect his total points. Therefore, the two cards have the same number, but opposite signs. We coluld pick any teo an an example: 6 and -6, or 4 and -4, etc. They don't affect his score since they ccancel each other with a result of zero.

5 0
3 years ago
The size of an insect population doubles every week. If there are 25 insects initially present, how many insects will there be i
Nata [24]

Answer:

tence there will be 6,00 insects abter 8 weeks.

Step-by-step explanation:

8 0
2 years ago
What is the value of 8^3+5x when x=12
Aleksandr-060686 [28]
8^3=512
5*12=60
512+60= 572
7 0
3 years ago
Read 2 more answers
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