2O3→3O2
The number of moles of O2 that are produced when 0.50 moles of O3(g) reacted is 0.75 moles
calculation and explanation
2 moles of O3(ozone) react to give 3 moles of O2 (oxygen gas,therefore the reacting ratio between O3 :O2 is 2:3
if 0.50 moles of O3 reacted then,by use of reacting ratio (2:3) find the moles of O2 produced
That is 0.50 x3/2 = 0.75 moles
Answer: option D) energy was absorbed and entropy increased.
Explanation:
1) Given balanced equation:
2H₂O (l) + 571.6 kJ → 2 H₂ (g) + O₂(g).
2) Being the energy placed on the side of the reactants means that the energy is used (consumed or absorbed). This is an endothermic reaction.
So, the first part is that energy was absorbed.
3) As for the entropy, it is a measure of the disorder or radomness of the system.
Since, two molecules of liquid water were transformed into three molecules of gas, i.e. more molecules and more kinetic energy, therefore the new state has a greater degree of radomness, is more disordered, and you conclude that the entropy increased.
With that, you have shown that the right option is D) energy was absorbed and increased.
Answer:
3.11%
Explanation:
We express a solution's volume by volume percent concentration, % v/v,
Take the ratio of the isopropyl alcohol (IPA) volume to the total volume of the solution, which is 1400 mL of water+ 45 mL of IPA,
and multiply by 100 to get the percentage: 45/(1400+45) *100 = 0.0311*100 = 3.11%
Volume of Ammonia(NH₃) = 22.4 L
<h3>Further explanation</h3>
Given
Reaction
3CuO+2NH₃⇒ 3Cu + 3H₂O+ N₂
<em>In the problem, the CuO coefficient should be 3 not 2</em>
M CuO = 80
mass CuO = 120 g
Required
The volume of NH₃
Solution
mol CuO :
From the equation, mol ratio CuO : NH₃ = 3 : 2, so mol NH₃=
Assume at STP(0 °C, 1 atm) ⇒1 mol = 22.4 L, then volume of NH₃=22.4 L
Answer:
Data:
mass of solute: 35g of NaCl
m.mass of solute: 58g/mol
volume of solution: 501mL
Molarity=?
Explanation:
501ml = 0.5dm3
M= g of solute/m.mass of solute*vol of solution
M= 35/58*0.5
M=1.20
